topic Re: screen in Application Development and Automation Discussions

screen

Former Member — Wed, 02 Apr 2008 07:47:48 GMT

Hello,

Please help me, i have made one screen there i have given one exit button when i am clicking exit button that programme have to leave programme.

I have wirrten the below mentioned codes. here i am not getting any error of my codes and when i am clicking exit it is not leaving the programme.

&----

*& Report ZSUJU

&----

REPORT ZSUJU.

Tables : zemp.

Data : it like zemp occurs 0 with header line.

&----

*& Module STATUS_2000 OUTPUT

&----

text

----

MODULE STATUS_2000 OUTPUT.

SET PF-STATUS 'ZUOM'.

SET TITLEBAR 'xxx'.

ENDMODULE. " STATUS_2000 OUTPUT

&----

*& Module USER_COMMAND_2000 INPUT

&----

text

----

MODULE USER_COMMAND_2000 INPUT.

CASE SY-UCOMM.

WHEN 'EXIT'.

LEAVE program.

ENDCASE.

ENDMODULE. " USER_COMMAND_2000 INPUT

Please let me know what i have to do more at your earliest and oblige.

Please do the needful urgently.

thanks,

sujatha

Re: screen

Former Member — Wed, 02 Apr 2008 07:59:00 GMT

Hi,

Give the type E where you create the layout of table control .

Rewards if helpfull.

Vijay

Re: screen

ak_upadhyay — Wed, 02 Apr 2008 08:03:48 GMT

Hi,

Give the function code EXIT to button in the properties.

GOTO ur screen > double click on the button > In FctCode

type exit > Save & Activate > then try

Reward points if useful....

Regards

Re: screen

Former Member — Wed, 02 Apr 2008 08:25:03 GMT

hi,

i think ak give you the right ans..................

GOTO ur screen > double click on the exit button >then a window apper see FctCode in fctcode write exit

Save & Activate > then try

ok try this

if useful give reward points

pankaj