topic Problem with SEARCH statement in the program in Application Development and Automation Discussions

Problem with SEARCH statement in the program

Former Member — Fri, 22 Feb 2008 18:39:13 GMT

I have below program:

DATA: V_1(03) TYPE C,

V_2 TYPE STRING.

V_1 = '9.0'.

SEARCH V_1 FOR '.' .

IF SY-SUBRC EQ 0.

REPLACE '.' IN V_1 WITH ' '.

ENDIF.

but search statement is not working,it sy-subrc eq 4.

Can anybody tell me why it is like this ?

Former Member — Fri, 22 Feb 2008 18:44:11 GMT

hi,

do this way...


DATA: V_1(03) TYPE C,
V_2 TYPE STRING.

V_1 = '9.0'.

REPLACE '.' IN V_1 WITH ' '.

Regards,

Santosh

Former Member — Fri, 22 Feb 2008 18:46:23 GMT

From F1 on SEARCH:

The statement SEARCH has been replaced with the statement FIND in Release 6.10.

The search patterns 'str' and '.str.' are identical apart from a few exceptions. You must

use '.str.' when the pattern str contains spaces (at the end), the '.' character (at the

beginning and end), or the '*' character (at the end). You should also use '.str.' when the

search string str is variable and you cannot predict when you write the statement what the

contents of the string will be.

This should work:

DATA: v_1(03) TYPE c,
v_2 TYPE string.

v_1 = '9.0'.

SEARCH v_1 FOR '...' .         <====

IF sy-subrc EQ 0.

  REPLACE '.' IN v_1 WITH ' '.

ENDI

But it will compress the space.

Rob

Edited by: Rob Burbank on Feb 22, 2008 1:48 PM

RichHeilman — Fri, 22 Feb 2008 19:02:32 GMT

Easy solution.....




DATA: V_1(03) TYPE C,
V_2 TYPE STRING.

V_1 = '9.0'.

TRANSLATE V_1 using '. '.

Regards,

Rich Heilman