topic Re: Routine Value in Application Development and Automation Discussions

Routine Value

Former Member — Mon, 07 Jan 2008 04:57:13 GMT

Hello friends,

I created a routine , i'm getting a problem of overlapping routine value for 2 conditions .

read table xkomv with key stunr = '103'.

IF SY-SUBRC EQ 0.

v_qty = xkomv-kawrt / 10.

if factor ne 0 .

conv_fac = ( xkomv-kbetr * factor ) / 10000000.

conv_fac = ( xkomv-kwert * 10000000 ) / factor .

endif.

read table xkomv with key kschl = 'ZR01'.

IF SY-SUBRC EQ 0.

xkomv-kbetr = ( conv_fac / v_qty ) * 100.

xkomv-kbetr = conv_fac.

xkomv-kpein = v_qty / 100 .
xkomv-kwert = conv_fac .

endif.

xkwert = ( conv_fac * v_qty ) / 100 .

clear conv_fac.

modify xkomv.

read table xkomv with key stunr = '105'.

if sy-subrc eq 0.

v_qty = xkomv-kawrt / 10.

if factor ne 0.

conv_fac = ( xkomv-kbetr * factor ) / 10000000.

endif.

read table xkomv with key kschl = 'ZR02'.

IF SY-SUBRC EQ 0.

xkomv-kbetr = conv_fac.

endif.

xkwert = ( conv_fac * v_qty ) / 100 .

This is the code where my value is overlapping here ..

please help me out for this.

Thanks& Regards

Lavanya

Re: Routine Value

Former Member — Mon, 07 Jan 2008 05:03:18 GMT

Yes, The Code is similar to both STUNR and KSCHL.

Exactly What help do u want ??

Re: Routine Value

Former Member — Mon, 07 Jan 2008 05:37:55 GMT

Hi ,

C let me explain u clearly .I'm picking some value where STUNR is 103 and i'm calculating some value n i'm putting that value where KSCHL is ZR01 ok . n next where stunr is 105 ...calculating something and putting that where kschl is ZR02.ok .now that final value is overlapping here ..

Re: Routine Value

Former Member — Mon, 07 Jan 2008 05:49:41 GMT

I think u shud write them in 2 routines.

i.e different routines for 103 and 105.

awrd points if useful

Bhupal