topic Re: String Manupilation in Application Development and Automation Discussions

String Manupilation

Former Member — Fri, 02 Nov 2007 12:42:39 GMT

Hi All,

I have a a char variable with a length of 18. As soon as this variable is populated, i want to fill the remaining lengths with spaces.

Does any1 have an idea how i can accomplish this?

Tks,

Danny

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 12:45:39 GMT

If it is char type...it will automatically fill rest length with space...

u dont need to code for it explicitely..

Reward useful answers,

Regards,

Tejas

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 12:48:25 GMT

Hi,

It will be populated automatically and if you need to remove you can use the CONDENSE statement.....

Thanks

Yogesh

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 12:55:31 GMT

Hi Tejas,

Let me explain futher what i am trying to do. I am trying make up a key for to read the lock table using FM ENQUEUE_READ. The key is made up of mandt, matnr (18 char), and plant.

Now i can do the above, except when the material number is made up of character. i:e

mandt = 100; matnr=testmaterial; plant=9090; When i concatenated it the result wil be 100testmaterial9090. But on sm12 the key is 100testmaterial 9090. The spaces in between is the remaining character of the length 18.

Tks,

Danny

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 13:02:18 GMT

You can try something like this :

concatenate mandt matnr to lv_key.

length = strlen( matnr ).

length = 18 - length.

do length times.

concatenate lv_key space to lv_key.

enddo.

concatenate lv_key plant to lv_key.

Regards

Nishant

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 13:37:44 GMT

Hi,

Thankx for the response. But the code still does not work correctly. I am getting this result : 050TestMat3091, instead of 050TestMat 3091.

Below is the code that i am using:

data: matnr(18) type c value 'TestMat',

plant type werks_d value '3091',

length type i,

lv_key(22) type c.

CONCATENATE sy-mandt matnr into lv_key.

length = strlen( matnr ).

length = 18 - length.

do length times.

concatenate lv_key space INTO lv_key.

enddo.

concatenate lv_key plant INTO lv_key.

WRITE: lv_key

tks,

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 13:53:36 GMT

Hi Danny,

Try this,

data: matnr(18) type c value 'TestMat',

plant type werks_d value '3091',

lv_key type string.

CONCATENATE mandt matnr plat INTO lv_key RESPECTING BLANKS.

Regards,

Amit

Message was edited by:

Amit Kumar

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 14:02:42 GMT

Hi Danny ,

Seems I found solution...check this code..


DATA: matnr(18) TYPE c VALUE 'TestMat',
plant TYPE werks_d VALUE '3091',
length TYPE i.

DATA : pv_key TYPE char22,
lv_key TYPE char26.

DATA : spc TYPE char18.

length = STRLEN( matnr ).

length = 18 - length.


CONCATENATE matnr plant INTO pv_key SEPARATED BY spc+0(length).
CONCATENATE sy-mandt pv_key INTO lv_key.

WRITE: lv_key.

Re: String Manupilation

Former Member — Fri, 02 Nov 2007 14:12:10 GMT

Excellent Perez. It works like a charm.

Thank you all for the response.