topic Re: plz help in Application Development and Automation Discussions

plz help

Former Member — Wed, 10 Oct 2007 08:01:57 GMT

Hi all,

i ahve a filed temp of type dec lenght 3 decimal 1.

now i have to assign 100.000000 (this comes from user, i ahve no control over it )to temp;

finally i want 100.0 in temp.

this is urgent for me.

Thanks in advacne

Amarender Reddy B

Re: plz help

Former Member — Wed, 10 Oct 2007 08:05:03 GMT

Hi,

DATA : TEMP1(3) TYPE P DECIMALS 3 VALUE '100.000000',
           TEMP2(3) TYPE P DECIMALS1.


TEMP2 = TEMP1.

WRITE :TEMP2.

Thanks.

Re: plz help

former_member188827 — Wed, 10 Oct 2007 08:06:15 GMT

try:

data temp type p LENGTH 3 DECIMALS 1.

data zval2 TYPE p DECIMALS 7 value '100.000000'.

temp = zval2.

WRITE / temp.

Re: plz help

Former Member — Wed, 10 Oct 2007 08:09:02 GMT

Hi,

try this:

data: DEC0 type p decimals 6.

data: dec1 type p decimals 1.

dec0 = '100.000000'.

dec1 = dec0.

write:/ dec0.

write:/ dec1.

or this:

data: dec1 type p decimals 1.

dec1 = '100.000000'.

write:/ dec1.

Regards, Dieter

Re: plz help

Former Member — Wed, 10 Oct 2007 08:12:23 GMT

the value which comes from user of length 16 decimal 6, this can any value

i ahve to assign this to length 3 deimal 1.

if i use = operator i am getting a short dump (runtime error) .

plz help

Re: plz help

Former Member — Wed, 10 Oct 2007 08:32:47 GMT

data : a(16) type p decimals 3,

b(3) type p decimals 1.

a = '100.000000'.

b = a.

write 😕 b.

This code is not giving short dump...just check it....!!!!

Re: plz help

Former Member — Wed, 10 Oct 2007 08:40:33 GMT

Hi,

if your input is allways a 16 lenght field with this structuter:

nnnnnnnnn.nnnnnn

you can use this:

data : c0(16),

c1(3) type p decimals 1.

c0 = '123456789.123456'.

c1 = c0+6(5).

write 😕 c0.

write 😕 c1.

Regards, Dieter