Simple yet complicated

Former Member — Thu, 13 Sep 2007 06:41:47 GMT

HI Guys!!

I need some extraordinary logic here...

Hope you can share yours..

scenario::

I have 2 fields:

field1 field2

1 a

2 b

3 c

2 d

1 a

3 e

I have two fields with respective values::

it seems simple but this is the problem.

I need to create a header wherein the value of field1 would be my first header then

the corresponding line item in field2 would be my second header. like this::

expected output::

1 2 3 <=field1 (if there are 3 same values let it be 1 avoid redundancy)

a a b d c e. <========field2 (second line corresponding values of field1 again if there are same values let it be 1 to avoid redundancy)

I dont know what kind of logic and coding would I be needing to achieve that.

I have 1 internal table w/c has field1 and field 2. everytime I sort field1 ,field2 is unsorted , vice versa.

Please experts , geeks!!ehehe..help me out!!!

Re: Simple yet complicated

Former Member — Thu, 13 Sep 2007 07:52:28 GMT

&----

*& Report ZTEST566 *

*& *

&----

*& *

&----

REPORT ZTEST566 .

data: begin of itb occurs 0,

f1 type i,

f2 type c,

end of itb.

data: begin of itb2 occurs 0,

f3 type i,

end of itb2.

data: begin of itb3 occurs 0,

f4 type c,

end of itb3.

itb-f1 = '1'.

itb-f2 = 'a'.

append itb.

clear itb.

itb-f1 = '2'.

itb-f2 = 'b'.

append itb.

clear itb.

itb-f1 = '3'.

itb-f2 = 'c'.

append itb.

clear itb.

itb-f1 = '2'.

itb-f2 = 'd'.

append itb.

clear itb.

itb-f1 = '1'.

itb-f2 = 'a'.

append itb.

clear itb.

itb-f1 = '3'.

itb-f2 = 'e'.

append itb.

clear itb.

data: number type i.

data: char_value(10) type c.

loop at itb.

itb2-f3 = itb-f1.

append itb2.

clear itb2.

endloop.

sort itb2 by f3.

delete adjacent duplicates from itb2 comparing f3.

loop at itb2.

write: itb2-f3.

endloop.

loop at itb2.

*read table itb with key f1 = itb2-f3.

loop at itb where f1 = itb2-f3.

itb3-f4 = itb-f2.

append itb3.

clear itb3.

endloop.

skip.

loop at itb3.

write: itb3-f4.

endloop.

<b>Hi this logic will do.

Please reward points if it helps.</b>

Thanks

Phani

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Simple yet complicated

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