topic Re: Simple Coding in Application Development and Automation Discussions

Simple Coding

Former Member — Fri, 31 Aug 2007 09:16:44 GMT

Hi,

When i execute the below coding , the output starts from the 8th postion of the list . Can anyone tell me y it starts from the 8th postion & not from the initial postion ?

data : A(10) type C value '200.22',

B(10) TYPE C VALUE '300.22',

C(10) TYPE C VALUE '400.22'.

DATA : N1 TYPE p decimals 2, N2 TYPE p decimals 2, N3 TYPE p decimals 2 .

N1 = A . N2 = B . N3 = C .

WRITE : / N1,

N2,

N3.

Re: Simple Coding

Former Member — Fri, 31 Aug 2007 09:19:09 GMT

Hi vighnesh,

1. By default, numbers are RIGHT-ALIGNED.

(thats why, it starts from 8th position)

2. If u want to print left aligned,

3. do like this.

report abc.

data : A(10) type C value '200.22',

B(10) TYPE C VALUE '300.22',

C(10) TYPE C VALUE '400.22'.

DATA : N1 TYPE p decimals 2, N2 TYPE p decimals 2, N3 TYPE p decimals 2

N1 = A . N2 = B . N3 = C .

<b>WRITE : / N1 LEFT-JUSTIFIED,

N2 LEFT-JUSTIFIED ,

N3 LEFT-JUSTIFI</b>

regards,

amit m.

Re: Simple Coding

Former Member — Fri, 31 Aug 2007 09:20:13 GMT

Hi,

This is because of the output length and the default alighment of variable N1/N2/N3...

Satya.

Re: Simple Coding

varma_narayana — Fri, 31 Aug 2007 09:30:24 GMT

Here the variable displayed first is N1 , which is of Type P.

By Default all numeric fields (I, P,F) are Right-justified in the Output.

The default length of Type P is 8 Bytes.

In 8 bytes it Can store the Value of 15 digits and the SIGN (-VE)

Thats why it is giving in 8ht position.

<b>reward if Helpful.</b>

Re: Simple Coding

Former Member — Fri, 31 Aug 2007 09:33:09 GMT

Hi Vighnesh,

you had declared the N1 variable type as pack decimals .

datatype pack can hold a max of 16 characters.

it can hold 2 decimal places by default and you had mentioned 2 decimals only.

the last character is empty because it will hold the sign ( + or -)

it starts from the 11 th position not from the 8th position .

value 200.22 has 6 characters and in the output it starts from 11th position.

check the code below.

DATA : a(15) TYPE c VALUE '1234567890200.223',

b(10) TYPE c VALUE '300.223',

c(10) TYPE c VALUE '400.223'.

DATA : n1 TYPE p DECIMALS 2,

n2 TYPE p DECIMALS 2,

n3 TYPE p DECIMALS 2.

START-OF-SELECTION.

n1 = a. n2 = b. n3 = c.

WRITE : n1 INPUT ON,

/ n2 INPUT ON,

/ n3.

reward points if useful.

phani.