topic Re: help in abap code logic in Application Development and Automation Discussions

help in abap code logic

Former Member — Mon, 27 Aug 2007 11:25:19 GMT

hallow

i have two tables that i wont to move the data(price) to third table itab

i wont to now how i can do that?

i reward kindly

i give the tabls.

INTAB_A132[]

resrc date knumh

0000123456 20070101 0000014834

0000123456 20070601 0000014835

2) intab_konp

knumh (key) kbetr(price)

0000014834 200000.00

0000014834 250000.00

this is what i have in table zempkostlprice_rec and i wont to add price colman

zempkostlprice_rec

rserc date

1 0000123456 012007

2 0000123456 022007

3 0000123456 032007

4 0000123456 042007

5 0000123456 052007

6 0000123456 062007

7 0000123456 072007

8 0000123456 082007

9 0000123456 092007

10 0000123456 102007

11 0000123456 112007

12 0000123456 122007

13 0000123456 012008

this is what i wont to add price colman to thired table from intab_konp

u can see that price have to be change after 01062007 to 250000

resrc date price

1 0000123456 012007 20000.00

2 0000123456 01022007 20000.00

3 0000123456 01032007 20000.00

4 0000123456 01042007 20000.00

5 0000123456 01052007 20000.00

6 0000123456 01062007 250000.00

7 0000123456 01072007 250000.00

8 0000123456 01082007 250000.00

9 0000123456 01092007 250000.00

10 0000123456 01102007 250000.00

11 0000123456 01112007 250000.00

12 0000123456 01122007 250000.00

13 0000123456 01 012008 250000.00

hi itry with that code but its not working i get in colman 2000000 in all rows

i thihk i have to take care in dates but i dont now how?

regards

LOOP AT zempkostlprice_rec INTO wa_zem.

READ TABLE intab_a132 INTO wa_intab_a132 WITH KEY resrc = wa_zem-resrc.

READ TABLE intab_konp INTO wa_intab_konp WITH KEY knumh = wa_intab_a132-knumh.

IF sy-subrc = 0.

wa_zem-kbetr = wa_intab_konp-kbetr.

MODIFY zempkostlprice_rec FROM wa_zem TRANSPORTING kbetr.

ENDIF.

ENDLOOP.

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 11:29:38 GMT

see for adding price fields u need to pass first the price and quantity fields to string then use the 'write to' statement ..................

reward points if helpful

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 11:47:54 GMT

plz experts

i need help im stuck

thankes

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 11:50:23 GMT

Thanks for ur points but i think still u havnt get ur answers correct.

Let me know proper requirements.

Regards,

Vimal

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 11:53:10 GMT

Create a new zprogram and put this code and check the values of internal tables in debugging mode

the price value chages according to knumh value becoz u have given intab_konp table which has common knumh so using this field only we can modify in ur zemp* table.

----

REPORT ZSHYTAL.

TYPES: BEGIN OF t_a132,

resrc LIKE a132-resrc,

kostl LIKE a132-kostl,

datbi LIKE a132-datbi,

datab LIKE a132-datab,

knumh LIKE a132-knumh,

END OF t_a132.

TYPES: BEGIN OF t_konp,

knumh LIKE konp-knumh,

kstbm LIKE konp-kstbm,

kbetr LIKE konp-kbetr,

konwa TYPE konp-konwa,

END OF t_konp.

types: begin of t_zemp,

RESRC like a132-resrc,

KOSTL LIKE a132-kostl,

kstbm LIKE konp-kstbm,

konwa TYPE konp-konwa,

kbetr LIKE konp-kbetr,

knumh LIKE konp-knumh,

END OF t_zemp.

DATA: intab_konp TYPE TABLE OF t_konp WITH HEADER LINE .

DATA : intab_a132 TYPE TABLE OF t_a132 WITH HEADER LINE .

data: it_zemp type TABLE OF t_zemp WITH HEADER LINE.

it_zemp-resrc = '0000123456'.

it_zemp-knumh = '0000014834'.

APPEND it_zemp.

it_zemp-resrc = '0000123456'.

it_zemp-knumh = '0000014834'.

APPEND it_zemp.

it_zemp-resrc = '0000123456'.

it_zemp-knumh = '0000014835'.

APPEND it_zemp.

intab_a132-resrc = '0000123456'.

intab_a132-knumh = '0000014834'.

intab_a132-datbi = '20070531'.

intab_a132-datab = '20070101'.

APPEND intab_a132.

intab_a132-resrc = '0000123456'.

intab_a132-knumh = '0000014835'.

intab_a132-datbi = '200701231'.

intab_a132-datab = '20070601'.

APPEND intab_a132.

intab_konp-knumh = '0000014834'.

intab_konp-kbetr = '20000'.

APPEND intab_konp.

intab_konp-knumh = '0000014835'.

intab_konp-kbetr = '25000'.

APPEND intab_konp.

clear: intab_konp, intab_a132, it_zemp.

LOOP at it_zemp. "into wa_zemp.

READ TABLE intab_a132 WITH KEY resrc = it_zemp-resrc.

READ TABLE intab_konp WITH key knumh = it_zemp-knumh.

if sy-subrc eq 0.

move intab_konp-kbetr to it_zemp-kbetr.

modify it_zemp." from wa_zemp.

ENDIF.

endloop.

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 11:54:58 GMT

try out this



LOOP AT zempkostlprice_rec INTO wa_zem.

READ TABLE intab_a132 INTO wa_intab_a132 WITH KEY resrc = wa_zem-resrc.
READ TABLE intab_konp INTO wa_intab_konp WITH KEY knumh = wa_intab_a132-knumh.


IF sy-subrc = 0.

wa_zem-kbetr = wa_intab_konp-kbetr.

MODIFY zempkostlprice_rec FROM wa_zem TRANSPORTING kbetr where zempkostlprice_rec = wa_zem-resrc .

ENDIF.

ENDLOOP.

regards.

Vijaykumar reddy. S

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 12:08:14 GMT

ho vimal

as u see i ahve in table zempkostlprice_rec fields date maybe i can use it becouse

the price is change in 01062007 and from this date the price is 2500000

i do some abap program but i never have problem like that

i look simple that is the problem

thankes for your time.

regards

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 12:42:21 GMT

hi vimal

there is more detail that u wont?

Regards

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 12:43:28 GMT

You are saying tht the values changes with response to date right.

can we hard code the value

LOOP at it_zemp. "into wa_zemp.

READ TABLE intab_a132 WITH KEY resrc = it_zemp-resrc.

READ TABLE intab_konp WITH key knumh = it_zemp-knumh.

if sy-subrc eq 0.

if it_zemp-date <= '01062007'. " this is hard code as per date.

it_zemp-kbetr = '2000000'.

modify it_zemp.

else

it_zemp-kbetr = '25000000'.

modify it_zemp.

endif. ENDIF.

endloop.

but i think this hardcode should not be done.

give ur spec i will go through it. let u know.

Regards,

Vimal

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 12:50:23 GMT

hi vimal

hard code is not helping becouse the tables all time change

there is no way to solve it in abap?

Regards

Re: help in abap code logic

Former Member — Mon, 27 Aug 2007 13:07:45 GMT

plz any one

i have big problem with that to much hours plz

can some one help to me or give idea

thankes