topic Re: How to enable/disable button on application tool based on some condition in Application Development and Automation Discussions

How to enable/disable button on application tool based on some condition

bikash_bansal — Fri, 24 Aug 2007 12:28:35 GMT

Hi,

I added an item to the application tool bar.

Its like a button which is displayed when the screen is called.

Now i want to enable and disable the button(item) based on some condition.

How to do that ???

Regards,

Bikash.

Re: How to enable/disable button on application tool based on some condition

JozsefSzikszai — Fri, 24 Aug 2007 13:12:49 GMT

hi Bikash,

you should do something like this:

IF condition is true

LOOP AT screen.

IF screen-name EQ button.

screen-active = 0.

MODIFY screen.

ENDIF.

ENDLOOP.

ENDIF.

hope this helps

Re: How to enable/disable button on application tool based on some condition

Former Member — Sat, 25 Aug 2007 07:39:05 GMT

to disable buttons in tool bar, check out option 'EXCLUDING' for ABAP command SET PF-STATUS.

If in a report, you can do something like:

SET PF-STATUS 'BASIC' EXCLUDING 'PICK' IMMEDIATELY.

In a dynpro screen:

DATA fcode TYPE TABLE OF sy-ucomm.

...

MODULE status_0100 OUTPUT. 
  APPEND 'CHANGE'  TO fcode. 
  APPEND 'SAVE' TO fcode. 
  SET PF-STATUS 'STATUS_0100' EXCLUDING fcode. 
ENDMODULE.

Andrew

Re: How to enable/disable button on application tool based on some condition

Former Member — Mon, 27 Aug 2007 11:44:15 GMT

you didnt specified report / module pool...

to enable/disable buttons on the application tool bar, use SET PF-STATUS.

Syntax

SET PF-STATUS status [OF PROGRAM prog] [EXCLUDING fcode].

at the starting of the program u might have specified a pf status.

say if u clik on a icon/button to disable it.. if its in the same program.

use command like

set pf-status 'ZSTATUS' excluding 'FCODE'.

if ur using PF status of some other program. specify the [OF PROGRAM prog]

set pf-status 'ZSTATUS' OF PROGRAM 'ZPRG' excluding 'FCODE'.

thanks

Re: How to enable/disable button on application tool based on some condition

bikash_bansal — Tue, 28 Aug 2007 10:40:27 GMT

Hi,

Using excluding is making it invisible. Its disappearing altogether.

I want it to be seen but being disabled.

My exact use case is :

I have a tree displayed and a action_button on the toolbar.

Whenever the root of the tree is selected i want to disable the action_button

and when a child of the tree is selected the action should be disabled.

How i added this button on the toolbar is :

module STATUS_0200 output.

SET PF-STATUS 'STATUS_0200' .

SET TITLEBAR 'TITLE_0200'.

endmodule.

After double clicking on 'STATUS_0200' i added a button on application tool bar.

Re: How to enable/disable button on application tool based on some condition

sharat_chandra — Wed, 29 Aug 2007 05:12:28 GMT

Hi,

You need to use a standard setting which specifies if you want to make visible a disabled button. Do as below :

In the GUI status screen, goto the the menu " GOTO"-> "ATTRIBUTES" ->"PUSHBUTTON ASSIGNMENT". In that you find the choices for disabled buttons: You need to choose "Display All".

Doing this, you will be able to see the disabled buttons also in an inactive state which are otherwise invisible.

Regards,

Sharat

Re: How to enable/disable button on application tool based on some condition

cesarscheck — Thu, 11 Jul 2013 13:51:03 GMT

This message was moderated.