topic Re: contains # in Application Development and Automation Discussions

contains #

Former Member — Fri, 06 Jul 2007 08:53:30 GMT

Hi,

I am trying to write the following code

if l_betrg ca '#'.

g_error = 'X'.

endif.

but even if l_betrg contains #, it is not going to g_error = 'X'

Could you please tell me where i am going wrong..I need to identify if l_betrg contains #. l_betrg is defined as

data: l_betrg(13) type c.

Thanks

Pranati

Re: contains #

Former Member — Fri, 06 Jul 2007 08:56:29 GMT

try this..

if l_betrg ca CL_ABAP_CHAR_UTILITIES=>HORIZONTAL_TAB.

g_error = 'X'.

endif.

OR

if l_betrg ca CL_ABAP_CHAR_UTILITIES=>CR_LF.

g_error = 'X'.

endif.

Re: contains #

amit_khare — Fri, 06 Jul 2007 08:58:09 GMT

Try this -

str1 type string value '#.

str2 type string.

move l_betrg to str2

if str2 cs str1.

g_error = 'X'.

endif.

Regards,

Amit

reward all helpful replies.

Re: contains #

Former Member — Fri, 06 Jul 2007 08:59:34 GMT

Your test case scenario doesn't happen... There might be a mistake in the content of the Variable... Please check the code.

Regards,

Pavan P.

Re: contains #

Former Member — Fri, 06 Jul 2007 09:00:32 GMT

Hi Praniti,

Use CP instead of CA.

Reward if useful!

Re: contains #

seshatalpasai_madala — Fri, 06 Jul 2007 09:01:13 GMT

Hi,

Check in debug mode if this actually contains '#' may its a case that it contains some value which is getting displayed as #.

Regards,

Sesh

Re: contains #

Former Member — Fri, 06 Jul 2007 09:02:24 GMT

Hi chandrashekar,

Just curious.. y did not my code work?

Re: contains #

former_member188827 — Fri, 06 Jul 2007 09:02:27 GMT

i tried ur code.its working absolutely fine!!

data i_betrg(13) type c.

data g_error(1).

i_betrg = '#1234'.

if i_betrg ca '#'.

g_error = 'X'.

endif.

write g_error.

rgds

Re: contains #

Former Member — Fri, 06 Jul 2007 09:02:43 GMT

Hi,

I think CA operator checks to see whether any letter in field1 is in field2.

Reward if helpful

Regards

Raghavendra.D.S

Re: contains #

Former Member — Fri, 06 Jul 2007 09:04:22 GMT

Hi,

actual probem is "#" is not a value.... its just showing the deliminator..... u cant use in the condition.... actually sap use it when its unidentified value

sign just determine the space or deliminator.....its actuall value is not a "#"... thats why your condition is being false..

regards,

shardul shah

Message was edited by:

Shardul Shah

Re: contains #

Former Member — Fri, 06 Jul 2007 09:04:38 GMT

it depends on the unicode , even i am not sure about that...

it works sometimes and sometimes not...