topic logic in Application Development and Automation Discussions

logic

Former Member — Tue, 03 Jul 2007 04:12:26 GMT

pls give the result...

I created a internal table .. as t1 in that i appended a,b,c,d

loop at t1.

write sy-index.

write sy-tabix.

endloop.

Re: logic

Former Member — Tue, 03 Jul 2007 04:16:47 GMT

HI,

sy-tabix will give u the table index.so in ur case it is 1,2,3,4

sy-index will give u the current loop index(do,while,...).

so it will give u 0 for each time.

so ur output is:01020304

rgds,

bharat.

Re: logic

Former Member — Tue, 03 Jul 2007 04:20:18 GMT

sy-index

sy-tabix

reward points if it is usefull....

Girish

Re: logic

Former Member — Tue, 03 Jul 2007 04:23:18 GMT

sy-tabix is 0

sy-index is no of records in the internal table (suppose if u have 5 records in the internal table then the sy-index is 5 (1 2 3 4 5)).

REMINDER: If you posted the question, please reward points for good answers*. Thanks.

Re: logic

Former Member — Tue, 03 Jul 2007 04:23:58 GMT

in loop at itab only sy-tabix getting incremented but in other loop like do enddo or while loop sy-index is getting incremented.

since you are using loop at itab.. so sy-tabix will get incremented from 1 to 4 because you have only 4 rows.... and sy-index is initial.

so output 01020304.

regards

shiba dutta

Re: logic

Former Member — Tue, 03 Jul 2007 04:26:50 GMT

HI,

Here there is differnece between sy-tabix and sy-index.

sy-tabix and sy-index will give the current loop pass value in the loop.

But here the differnece is sy-tabix must be used in the loop at - endloop only.

Sy-index must be used in the other loop like Do-Enddo.

So in your scenario you have used both sy-tabix and sy-index in loop at -endloop.

Here sy-tabix will give the current loop pass value i.e. during first loop pass it gives sy-tabix as 1 and during second loop pass it gives as 2 so on.

But here sy-index value does not change i.e.whatever the sy-index value before the loop at that will mainitan.Here let assume before loop at sy-index is 0 then after every loop pass also sy-index is 0.

So simply in your logic sy-tabix will give current loop pass value but sy-index has no effect and it does not change.

Thanks and regards,

shyla

Re: logic

Former Member — Tue, 03 Jul 2007 04:36:07 GMT

Hi,

output will be 0 1 0 2 0 3 0 4

bcoz sy-index is 0 and sy-tabix will change from 1-4.

also, this is my codes where i hv tried.

DATA: BEGIN OF itab occurs 0,
index type int4,
END OF itab,
wa like line of itab.

do 4 times.

wa-index = sy-index.
append wa to itab.
enddo.

loop at itab.
write: sy-index.
write: sy-tabix.

endloop.

Jogdand M B

Re: logic

Former Member — Tue, 03 Jul 2007 04:40:22 GMT

Hi,

loop at t1.

write sy-index.

write sy-tabix.

endloop.

Output for your program is:4, because you didn't use '/' in each write statement, so you change your program by given below

loop at t1.

write / 'index:',sy-index.

write / 'tabix:',sy-tabix.

endloop.

OUTPUT:

***********

index:0

tabix:1

index:1

tabix:2

index:2

tabix:3

index:3

tabix:4

index will start from 0 and tabix will start from 1.

IF USEFULL REWARD