topic Re: Simple Correction to the code in Application Development and Automation Discussions

Simple Correction to the code

Former Member — Wed, 23 May 2007 07:29:48 GMT

Data : V1(10) type c value ' 123-',

sign_flag(1).

IF V1 < 0.

V1 = V1 * -1 .

sign_flag = 'X'.

ENDIF.

CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'

EXPORTING

INPUT = V1

IMPORTING

OUTPUT = V1.

IF sign_flag = 'X'.

V1 = - ( V1 ).

ENDIF.

Write : V1.

<b>Above code is for Padding Leading Zeroes to Negative Number stored in field V1 with Data type C(10).</b>

Output of above code is = 123-

But I want it to be = 000000123-

How I can do that.

Do the correct modifications in the program.

Points will be given to the good ones.

Regards

Message was edited by:

Tulip Shah

Re: Simple Correction to the code

dev_parbutteea — Wed, 23 May 2007 07:36:21 GMT

use

'CONVERSION_EXIT_ALPHA_OUTPUT'

Re: Simple Correction to the code

Former Member — Wed, 23 May 2007 07:39:57 GMT

use this code/.....

Data : V1(10) type c value ' 123-',

v2(10) TYPE n,

v3(11) TYPE n,

sign_flag(1).

IF V1 < 0.

V1 = V1 * -1 .

sign_flag = 'X'.

ENDIF.

CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'

EXPORTING

INPUT = V1

IMPORTING

OUTPUT = V1.

IF sign_flag = 'X'.

V1 = - ( V1 ).

ENDIF.

*v2 = v1.

move v1 to v2.

CONCATENATE v2 '-' into v3.

Write 😕 V1, / v3.

With Regards,

S.Barani

Re: Simple Correction to the code

Former Member — Wed, 23 May 2007 07:45:52 GMT

IF sign_flag = 'X'.

V1 = '- 0000123'.

ENDIF.

Write : V1(10).

do this correction in ur code ..

bhanu

Re: Simple Correction to the code

Former Member — Wed, 23 May 2007 07:46:38 GMT

No question of using the fun module

it is of no use

it won't accept signs.

use the following code.

it will work

Data : V1(10) type c value ' 123-',

n2(10) TYPE n,

n3(11) TYPE n,

sign_flag(1).

IF V1 < 0.

V1 = V1 * -1 .

sign_flag = 'X'.

ENDIF.

IF sign_flag = 'X'.

V1 = - ( V1 ).

ENDIF.

move v1 to n2.

CONCATENATE n2 '-' into n3.

Write 😕 n3.

Reward points if useful

Regards

Anji

Re: Simple Correction to the code

Former Member — Wed, 23 May 2007 08:22:45 GMT

Thanks for all your replys

All above answers are not meeting my requirement.

Regards

Re: Simple Correction to the code

Former Member — Wed, 23 May 2007 08:23:42 GMT

Thanks

Re: Simple Correction to the code

dev_parbutteea — Wed, 23 May 2007 08:29:05 GMT

Hi,

try this out:

num = strlen(V1)

num2 = 10 - num.

do num2 times.

concatenate '0' V1 into V1.

enddo.

Reward if helpful,

Regards,

Sooness.