topic Re: Concatenating in Application Development and Automation Discussions

Concatenating

Former Member — Tue, 08 May 2007 06:50:35 GMT

Hi Friends,

I need to concatenate the last two characters of the string can any one tell me how to do it.

Y94701000000000LS

With Regards,

Line

Re: Concatenating

Former Member — Tue, 08 May 2007 06:53:59 GMT

Using Offset operator you can do that.

First get the string length and get the last characters of the variable

length = length of string.

length = length -2.

concatenate v1+length(2) -

I hope this will help you.

Warm Regards,

Vijay

Re: Concatenating

Former Member — Tue, 08 May 2007 06:54:51 GMT

Hi,

Data : v1(2),

v2(2),

v3(4).

v1 = 'AB'.

v2 = 'CD'.

Concatenate v1 v2 into v3.

Reward points if it is helpful.

Regards,

Sangeetha.A

Re: Concatenating

Former Member — Tue, 08 May 2007 06:55:36 GMT

Hi..

to which field u want to concatenate??

any how..

data:

w_string type string,

len type i.

w_string = 'Y94701000000000LS'.

len = strlen( w_string ).

len = len - 2.

concatenate w_string+len(2) 'ABCD' into new_string.

Re: Concatenating

Former Member — Tue, 08 May 2007 06:57:53 GMT

Hi,

Constants: c_l type c value 'L',

c_s type c value 'S'.

data: s_target(17) type c value 'Y94701000000000'.

concatenate c_l c_s into s_target.

or you can define it as single constant

constants: c_ls(2) type c value 'LS'.

concatenate c_ls s_target into s_string.

where s_string is a new variable.

Asha

Re: Concatenating

Former Member — Tue, 08 May 2007 07:17:57 GMT

Hi Ram,

What is 'ABCD'.

Line

Re: Concatenating

dev_parbutteea — Tue, 08 May 2007 07:30:43 GMT

'ABCD' is just a string he is using to show concatenation with last 2 characters of w_string

Re: Concatenating

Former Member — Tue, 08 May 2007 07:46:35 GMT

Hi there,

pls check my code i am getting error message 'Char like field expected after v_tempstr+len(2).

Code :

v_tempstr = i_prpx-posid4.

len = strlen( v_tempstr ).

if len > 14.

len = v_chrg - 2.

concatenate v_tempstr+len(2) into v_chrg.

i_bseg-posid5 = v_chrg.

endif.

Regards,

Line

Re: Concatenating

dev_parbutteea — Tue, 08 May 2007 07:51:10 GMT

Hi,

Line , you have not put anything after v_tempstr+len(2) field, thats y it says char like field expected!

concatenate v_tempstr+len(2) put something here into v_chrg.

Re: Concatenating

Former Member — Tue, 08 May 2007 07:58:00 GMT

Hi,

This error occurs because when You're using CONCATENATE' command

You have to give it anleast 2 arguments (2 strings or chars).

In Your code:

concatenate v_tempstr+len(2) into v_chrg.

You have only 1 argument.

Solution:

1) v_chrg = v_tempstr+len(2).

2) use CONCATENATE but give more arguments f.e.

concatenate v_tempstr+len(2) second argument into v_chrg.

Message was edited by:

Artur Cywinski

Re: Concatenating

Former Member — Tue, 08 May 2007 08:11:24 GMT

Hi there,

But When I am keeping something after that statement it is also adding.

like i want to concatenate this string 'Y94701000000000LS'

I used the following code:

v_tempstr = i_prpx-posid4.

len = strlen( v_tempstr ).

if len > 14.

len = len - 2.

concatenate v_tempstr+len(2) 'XYZ' into v_chrg.

i_bseg-posid5 = v_chrg.

endif.

I am getting LSXYZ in the field v_chrg.

Pls tell me what to do.

Regards,

Line

Re: Concatenating

Former Member — Tue, 08 May 2007 08:54:53 GMT

Hi Line,

What is the value stored in the v_tempstr?

If it is 'Y94701000000000LS', then you will get '15' for len so v_tempstr+15(2) will extract 'LS' from v_tempstr.

After that, concatenate 'LS' 'XYZ' will become 'LSXYZ' which is same as the result that you got. Is this the result you want?

What are you exepected result that will store in the v_chrg?