topic Re: syntax in Application Development and Automation Discussions

syntax

Former Member — Thu, 29 Mar 2007 08:48:55 GMT

hi,

the syntax not right.

may i know how to code it correctly?

thanks

IF wa-acc IS INITIAL OR

wa-acc+0(1) NOT IN ( '5','6','7' ) OR

wa-acc+0(2) NOT IN ( 'LA' , 'IA' ).

CONTINUE.

ELSE.

do something.

ENDIF.

Re: syntax

Former Member — Thu, 29 Mar 2007 08:55:40 GMT

Hi El,

You cannot use the not in() in the if condition.

The Not In() statement is used in where statements.

Regards,

Ravi.

Re: syntax

Former Member — Thu, 29 Mar 2007 08:57:53 GMT

hi,

thanks.

so what can i do on this?

Re: syntax

Former Member — Thu, 29 Mar 2007 09:01:24 GMT

Try this..

IF wa-acc IS INITIAL OR
   NOT wa-acc+0(1)  IN ( '5','6','7' ) OR
   NOT wa-acc+0(2)  IN ( 'LA' , 'IA' ).
CONTINUE.
ELSE.
do something.
ENDIF.

Re: syntax

Former Member — Thu, 29 Mar 2007 09:05:14 GMT

You can use this

<b>NA Contains Not Any:</b> True if a logical expression with CA is false, that is if operand1 does not contain any characters from operand2. If the result of the comparison is negative, sy-fdpos contains the offset of the first character in operand1 that is also contained in operand2. If the result of the comparison is true, sy-fdpos contains the le of operand1.

Assign points if it helps.

-Gaurang

Re: syntax

Former Member — Thu, 29 Mar 2007 09:06:30 GMT

hi,

this is incorrect.

rgds

Re: syntax

Former Member — Thu, 29 Mar 2007 09:12:28 GMT

case wa-acc+0(2)

when LA'

x= p

when AA'

x= Q

if IF wa-acc IS INITIAL OR

wa-acc+0(1) nc '567' or x ne p or X ne q.

CONTINUE.

ELSE.

do something.

ENDIF.

Message was edited by:

sunil kumar