timeout for startrfc program?

Former Member — Tue, 12 Oct 2004 13:55:34 GMT

Dear all,

I have a unix script, which calls a function module via the startrfc program. Sometimes the program does not terminate or at least it runs very long due to problem within the SAP system. Is there a option to start the startrfc program with a time threshold, so that it terminates, if it does not get result after a given time? (i.e. is there a "rdisp/max_wprun_time parameter" on OS level).

thanks in advance for your comments

Richard

Re: timeout for startrfc program?

Former Member — Tue, 12 Oct 2004 14:23:34 GMT

In short, I don't believe so.

If you look at the C code for startrfc (...\sapgui\rfcsdk\text directory), you can see that it uses RFC function RfcCallReceive.

RfcCallReceive is a blocking call that has no option for timeout. If this is not satisfactory, you could change the code to call functions RfcCall, RfcListen and RfcReceive instead (my C is rusty):


  rc = RfcCall(...);

  if rc == RFC_OK
  {
    do
    {
      // Wait for timeout or call is finished
    }
    while TimedOut || ( rc = RfcListen(...) ) == RFC_RETRY );
  }

  if !TimedOut && ( rc == RFC_OK )
  {
    rc = RfcReceive(...);
  }

It is then your responsibility to set the internal timeout as you see fit.

Cheers,

Scott

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timeout for startrfc program?

Re: timeout for startrfc program?