topic Re: Find a '(' in a string? in Application Development and Automation Discussions

Find a '(' in a string?

Former Member — Thu, 02 Sep 2004 08:57:51 GMT

Hello,

I have the following code.


DATA: tmp TYPE STRING,
      result TYPE i.

tmp = 'Craig (Cmehil)'.
IF tmp CS '('.
  result = 1.
ENDIF.

write: / result.

IF tmp NS '('.
  result = 0.
ENDIF.

write: / result.

However the result should be 1 and then 0 but I get 1 and then 1 again.

How can I find the ( inside of a string?

Re: Find a '(' in a string?

Former Member — Thu, 02 Sep 2004 09:04:49 GMT


DATA: tmp TYPE STRING.

tmp = 'Craig (Cmehil)'.

write: / tmp.

IF tmp CA '#('.
  tmp = 'Found'.
ELSE.
  tmp = 'Not Found'.
ENDIF.

write: / tmp.

Sometimes sitting back and thinking and you get that whole apple on the head realization

Re: Find a '(' in a string?

MalaGo — Thu, 02 Sep 2004 09:21:20 GMT

Hi,

you can use SEARCH f FOR g to find string g in string f.

Regards,

Malgorzata

Message was edited by: Malgorzata Jaworek

Re: Find a '(' in a string?

Former Member — Thu, 02 Sep 2004 09:36:52 GMT

Hi,

you will not get a 1 in second case.

just think over again. what you are trying is in the first instance trying to see if the '(' is part of the string. which is yes, so it goes in ans set result to 1.

But in the second case you set result to 0 only when the string shouldn't contain '('. But since in your case it contains '(' it won't go in.

Re: Find a '(' in a string?

Former Member — Thu, 02 Sep 2004 10:21:40 GMT

Actually the logic in the first post was completely wrong but my second post shows how I solved my own problem. Just didn't have my eyes open is all

Re: Find a '(' in a string?

Former Member — Fri, 03 Sep 2004 06:18:12 GMT

Hello Craig,

Use following statement. It works allways.

if ls_text CP '('.

do soething.

endif.

Michael

Re: Find a '(' in a string?

Former Member — Sat, 04 Sep 2004 05:30:19 GMT

Hi,

There is one more option, this will also work

IF char CN '+-*/=~#^[]\&%$@.,;:"!}{'.

-- do the job --

ENDIF

Prabhu Rajesh.