date calculation

Former Member — Sat, 17 Feb 2007 13:52:12 GMT

Could someone explain me the following from the code below:-

q1]] How do we get "80049488" in the 1st output?

q2]] why there is no difference between the outputs in the 3rd & 4th cases?:

q3]] what is the possible answer to the question "Inverted Dates"?

Inverted Dates

In some cases (for example, when sorting dates in descending order), it is useful to convert a

date from format D to an inverted date by using the keyword CONVERT

CONVERT DATE <d1> INTO INVERTED-DATE <d2>.

Afterwards, you can convert the inverted data back into a normal date using the statement

CONVERT INVERTED-DATE <d1> INTO DATE <d2>.

These statements convert the field <d1> from the formats DATE or INVERTED-DATE to the

formats INVERTED-DATE or DATE and assign it to the field <d2>.

For the conversion, ABAP forms the nine's complement.

DATA: ODATE TYPE D VALUE '19955011',

IDATE LIKE ODATE.

DATA FIELD(8).

FIELD = ODATE. WRITE / FIELD.

CONVERT DATE ODATE INTO INVERTED-DATE IDATE.

FIELD = IDATE. WRITE / FIELD.

CONVERT INVERTED-DATE IDATE INTO DATE ODATE.

FIELD = ODATE. WRITE / FIELD.

Output:

80049488

19955011

1995501

Re: date calculation

Former Member — Sat, 17 Feb 2007 17:52:21 GMT

Hi,

I am not sure if the output mentioned by you is correct. I got the followed the same code and got the following output:

19955011

80044988

19955011

The principle is simple as you would already have discovered,

inversion 1 = 99999999 - date

back = 99999999 - date

Hope this helps.

Cheers,

~i1