topic Re: Help in Application Development and Automation Discussions

Help

Former Member — Sun, 04 Feb 2007 06:39:08 GMT

I'm using LINK and LINP tables.... I don't know why in my output I'm not getting lgtyp and uname filled.

Re: Help

Former Member — Sun, 04 Feb 2007 06:42:13 GMT

Shaheen,

Can you please provide your selection code for these two tables?

Thanks.

Re: Help

Former Member — Sun, 04 Feb 2007 06:46:53 GMT

First table:

select lgnum ivnum ivpos istat lgpla idatu from linp into

corresponding fields of table itab where lgnum = pa_lgnum and ivnum

in s_ivnum.

Second table:

select lgnum ivnum lgtyp uname FROM link INTO CORRESPONDING

FIELDS OF TABLE itab1 where lgnum = pa_lgnum AND ivnum IN s_ivnum.

Re: Help

Former Member — Sun, 04 Feb 2007 06:51:25 GMT

Hi,

Can you also provide the Internal table structures(itab and itab1)?

Srini

Re: Help

Former Member — Sun, 04 Feb 2007 06:58:59 GMT

Types: begin of str1_tab,

lgnum type lgnum,

ivnum type LVS_IVNUM,

ivpos type LVS_IVPOS,

lgtyp type lgtyp,

lgpla type lgpla,

idatu type LVS_IDATU,

uname type LINK_UNAME,

end of str1_tab.

Data: itab type table of str1_tab,

wa_tab like line of itab,

wa_linp type linp,

wa_link type link.

DATA: itab1 TYPE TABLE OF str2_tab,

wa_tab1 LIKE LINE OF itab1.

Types: begin of str2_tab,

lgnum type lgnum,

charg type CHARG_D,

ivnum type LVS_IVNUM,

ivpos type LVS_IVPOS,

istat type LINV_ISTAT,

lgtyp type lgtyp,

lgpla type lgpla,

matnr type matnr,

uname type LINK_UNAME,

idatu type LVS_IDATU,

end of str2_tab.

Data: itab1 type table of str2_tab,

wa_tab1 like line of itab1,

wa_linv type linv.

Re: Help

Former Member — Sun, 04 Feb 2007 07:01:17 GMT

Shaheen,

LINK is header table and LINP is item table so your first table should be LINK to improve the performance:

Write the code as below:

select lgnum ivnum lgtyp uname FROM link INTO CORRESPONDING

FIELDS OF TABLE itab1 where lgnum = pa_lgnum AND ivnum IN s_ivnum.

select lgnum ivnum ivpos istat lgpla idatu from linp into

corresponding fields of table itab for all entries in table itab1 where lgnum = itab-lgnum and ivnum = itab-ivnum.

And then you will have to populate the respective fields in to the final table.

There is one better option of writting a JOIN statement which do not require above select statements:

Write code as below

TABLES: link, linp.

data: begin of itab occurs 0,

lgnum like link-lgnum,

ivnum like link-ivnum,

lgtyp like link-lgtyp,

uname like link-uname,

ivpos like linp-ivpos,

istat like linp-istat,

lgpla like linp-lgpla,

idatu like linp-idatu,

end of itab.

parameters: pa_lgnum like link-lgnum.

select-options: s_ivnum for link-ivnum.

select a_{lgnum a}ivnum a_{lgtyp a}uname b_{ivpos b}istat b_{lgpla b}idatu

from link as a

inner join linp as b on a_{lgnum = b}lgnum and a_{ivnum = b}ivnum

into table itab

where a~lgnum = pa_lgnum

and a~ivnum in s_ivnum.

The table ITAB will have all required fields populated.

Let me know if this works.

Thanks

Re: Help

Former Member — Sun, 04 Feb 2007 07:14:11 GMT

sorry but none of them are wroking

Re: Help

Former Member — Sun, 04 Feb 2007 07:15:21 GMT

Shaheen,

Can you please post your complete code??

The above should work in the report......

Re: Help

Former Member — Sun, 04 Feb 2007 07:36:21 GMT

mine is a report too

Re: Help

Former Member — Sun, 04 Feb 2007 08:09:22 GMT

Hey Shaheen,

The Code looks fine...can you check the entries in the table(se16)

for the values you are entering int the parameters and the select-option, i think the table does have any values stored for your selection cretirea..

Srini.