topic Re: IS THIS VALID in Application Development and Automation Discussions

IS THIS VALID

Former Member — Sat, 27 Jan 2007 08:00:15 GMT

I WOULD LIKE TO KNOW IF THIS IS CORRECT

IF EQUI-ANSDT BETWEEN 'O1.O4.1992' AND '31.03.1993'.

AMT = ( AMT1 * 8.24 ) / 100 .

AMT2 = AMT1 - AMT.

CLEAR AMT.

IT GIVES ME THE ERROR :

INCOMPLETE ARTHIMETIC EXPRESSION.: ")" MISSING AT END OF STMT.

PLS HELP,

CAPC

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 08:03:12 GMT

IF EQUI-ANSDT ge '19920401' or EQUI-ANSDT le '19930331'.

AMT = ( AMT1 * 8.24 ) / 100 .

AMT2 = AMT1 - AMT.

CLEAR AMT.

endif.

if EQUI-ANSDT is a date field.

regards

shiba dutta

Re: IS THIS VALID

anversha_s — Sat, 27 Jan 2007 08:16:23 GMT

hi,

try this.

IF ( EQUI-ANSDT  GE  '19920401'  AND  EQUI-ANSDT  LE '19930331' ).

AMT = ( AMT1 * 8.24 ) / 100 .
AMT2 = AMT1 - AMT.
CLEAR AMT.

Rgds

Anver

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 08:42:23 GMT

sorry anver is right in if condition instead of or it will be and please change that.

regards

shiba dutta

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 09:38:01 GMT

Date format is different in different systems according to the user profile settings.

So , please make the below. It will work in any system.

Date : lv_date1 like equi-ansdt,

lv_date2 like equi-ansdt.

Move the dates :

lv_date1 = s_ansdt-low.

lv_date2 = s_ansdt-high.

If ( equi-ansdt >= lv_date1 ) and ( equi-ansdt <= lv_date2 ).

amt = ( amt * 8.24 ) / 100.

amt2 = amt1 - amt.

clear amt.

endif.

The above thing will work out.

Reward Points if helpful and close the thread.

Kannu.

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 09:56:50 GMT

Hi kannu,

my problem is not with the if condition,

but the

amt = ( amt * 8.24 ) / 100 stmt.....

i gave amt as type i.

is it oK, pls help

capc

Re: IS THIS VALID

anversha_s — Sat, 27 Jan 2007 09:57:28 GMT

hi,

Please mark all helpful answers.

Regards

Anver

Re: IS THIS VALID

anversha_s — Sat, 27 Jan 2007 10:08:07 GMT

hi,

chk this.

data : f_val type f value '8.24'.

AMT = ( AMT1 *  f_val ) / 100 .

AMT2 = AMT1 - AMT.

CLEAR AMT.

this will work

Rgds

Anver

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 10:22:57 GMT

amt = ( amt * 8.24 ) / 100

It depends on how you need to have the result, if you use an integer the result will be rounded off :

DATA: AMT TYPE I VALUE 200.

AMT = ( AMT * '8.24' ) / 100.

* ---> 200 * 8.24 / 100 = 16.48 =======> AMT = 16

DATA: AMT TYPE I VALUE 300.

AMT = ( AMT * '8.24' ) / 100.

* ---> 300 * 8.24 / 100 = 24.72 =======> AMT = 25

Max

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 10:35:36 GMT

Hi anver,

but the values are from parameters......

thanks,

CAPC

Re: IS THIS VALID

Former Member — Sat, 27 Jan 2007 10:47:26 GMT

Hi CAPC,

I believe you have to give a space after )

Best Regards

Renjan