topic Re: Charater to string in Application Development and Automation Discussions

Charater to string

Former Member — Sat, 14 Oct 2006 06:29:24 GMT

Hi Friends,

I am capturing the numbers in selection screen parameter. eg: 10.

Later I am using this value concatenating with some word. Eg. Test.

The result i am getting is '010 Test'.

How to get the result as '10 Test'. (The '0' appearing before to 10 should be avoided).

Also how I can add 1 to parameter value. (10 + 1 = 11).

Eg. 11 Test.

Could u pls guide me.

TIA.

Regards,

MARK K

Re: Charater to string

anversha_s — Sat, 14 Oct 2006 06:34:35 GMT

hi,

try to use,

Fm -> CONVERSION_EXIT_ALPHA_OUTPUT (removing zeros)

rgds

anver

Message was edited by: Anversha s

Re: Charater to string

Former Member — Sat, 14 Oct 2006 06:34:50 GMT

HI Mark

How about using SHIFT Left statement before concatenating.

Eg:

   shift <fld1> left deleting leading '0'.
   concantenate <fld1> 'Test' into <fld2> separated by space.

Also have a look at PACK/UNPACK statements.

Kind Regards

Eswar

Re: Charater to string

Former Member — Sat, 14 Oct 2006 06:50:49 GMT

Hi Eswar,

Removing '0' is solved. But, how I can increment the value by 1. ie., I have to change the character type to integer. How to do that.

Regards,

Re: Charater to string

Former Member — Sat, 14 Oct 2006 06:54:23 GMT

Hi,

Try this function CONVERT_STRING_TO_INTEGER

check the below code which will convert character to integer..

DATA NO1(10) TYPE C VALUE '1234567890'.

DATA NO2 TYPE I.

NO2 = NO1.

WRITE NO2.

the foll code will convert the string to interger.

DATA NO1 TYPE STRING.

DATA NO2 TYPE I.

NO1 = '1234567890'.

NO2 = NO1.

WRITE NO2.

hope this helps

Regards

Alfred

Re: Charater to string

Former Member — Sat, 14 Oct 2006 07:03:07 GMT

Hi Mark

No need of conversion to integer if we declare the initial variable of type 'N'.

Please see this example for some understanding:

data: l_num(3) type n value '010'.
data: l_text(20) type c.

  perform print using l_num.
  l_num = l_num + 1.
  perform print using l_num.

  form print using l_num.
    shift l_num left deleting leading '0'.
    concatenate l_num 'Test' into l_text separated by space.
    write:/ l_text.
  endform.

Am not on SAP, so please bear if there are any syntax errors.

Kind Regards

Eswar