topic Re: reading a string. in Application Development and Automation Discussions

reading a string.

Former Member — Thu, 05 Oct 2006 10:23:56 GMT

Hi experts.

how can i read a string at a specified character.

For ex: i have astring like this.

str = 'YUGFHKGHKHDKHHHGJK8HJBFXJKKFKJFJKFHJH'.

so i have to read n.of charecters from starting of the string to charecter 8.

Not with search option.

Regards

Re: reading a string.

Former Member — Thu, 05 Oct 2006 10:24:55 GMT

sorry:

do tis way:

split str at '8' into V_one v_two.

v_two would have the string you need.

Regards,

ravi

Message was edited by: Ravi Kanth Talagana

Re: reading a string.

Former Member — Thu, 05 Oct 2006 10:27:50 GMT

data str(100).

str = 'YUGFHKGHKHDKHHHGJK8HJBFXJKKFKJFJKFHJH'.

search str for '8'. write sy-fdpos.

Max

Re: reading a string.

Former Member — Thu, 05 Oct 2006 10:28:22 GMT

Hi,

Fidn the String lenght first,

DATA: Len type i.

String: STR.

str = 'YUGFHKGHKHDKHHHGJK8HJBFXJKKFKJFJKFHJH'.

Len = STRLEN(STR).

in the LEN will have the total lenght, now using the offset you can read as you want ..

Hope you understand

Regards

Sudheer

Re: reading a string.

Former Member — Thu, 05 Oct 2006 10:29:31 GMT

SPLIT str AT '8' into str1 str2.

str1 has the string from start to 8

and str2 from 8 to end.

If you can have more 8 in the strings than you need to include more variables.

If str CS '8'.

lpos = sy-fdpos - 1.

write str(lpos) to str1.

endif.

Message was edited by: Anurag Bankley

Re: reading a string.

Former Member — Thu, 05 Oct 2006 10:34:41 GMT

Hi Ravi,

You can use the offset technique to get certain part of a string

str = 'YUGFHKGHKHDKHHHGJK8HJBFXJKKFKJFJKFHJH'.

v_temp = str+0(8).

where 0 is the starting position and 8 is the length of the string

so now v_temp will contain YUGFHKGH

Re: reading a string.

Former Member — Thu, 05 Oct 2006 12:33:59 GMT

Hi,

Thank you all.

I know all these but in my program it is not workig..Don't know why...

either split or search.Pls see the below sample code.

DATA : i_files like spflist occurs 0 with header line,

DATA: w_files LIKE LINE OF i_files.

data: str1(200) type c,

str2(200) type c.

LOOP AT i_files INTO w_files.

str = w_files-line.

lin1 = STRLEN( str ).

lin1 = lin1 - 1.(this is because there is one more '#' at the end of string)

str = str+0(lin1).

lin2 = STRLEN( str ).

search str for '#'.

split str at '#' into str1 atr2.

w_files-line = str.

MODIFY i_files FROM w_files.

CLEAR lin1.

ENDLOOP.

Suppose here str contains:

str = '00000003379#212RegVNegNoticeHLA.aspx.xml'.

So i am getting sy-subrc = 4 after search.

and after split there are no values in str2..and str1 contains full string..

Can any body tell me what may be the problem..?

Regards

Re: reading a string.

Former Member — Thu, 05 Oct 2006 12:43:01 GMT

Hi Ravi,

 Your code works perfectly in my system,

 chk yhis

REPORT YCHATEST.

DATA : I_FILES LIKE SPFLIST OCCURS 0 WITH HEADER LINE.
DATA: W_FILES LIKE LINE OF I_FILES.
DATA: STR1(200) TYPE C,
STR2(200) TYPE C,
STR(200),
LIN1 TYPE I,
LIN2 TYPE I.

I_FILES-LINE = '00000003379#212RegVNegNoticeHLA.aspx.xml#'.
APPEND I_FILES.
CLEAR I_FILES.

LOOP AT I_FILES INTO W_FILES.
  STR = W_FILES-LINE.
  LIN1 = STRLEN( STR ).
  LIN1 = LIN1 - 1.
  STR = STR+0(LIN1).
  LIN2 = STRLEN( STR ).
  SEARCH STR FOR '#'.
  SPLIT STR AT '#' INTO STR1 STR2.
  W_FILES-LINE = STR2.
  MODIFY I_FILES FROM W_FILES.
  CLEAR LIN1.
*  WRITE : / W_FILES-LINE.
ENDLOOP.

Re: reading a string.

Former Member — Thu, 05 Oct 2006 12:48:14 GMT

Though in debugging, some characters resemble '#', in real they might not be. For these cases, searching or splitting with '#' will not work. Kindly check the source of the data to recognize the same.

Kind Regards

Eswar

Re: reading a string.

Former Member — Thu, 05 Oct 2006 13:17:28 GMT

Since the search results in subrc = 4. It means that it is not # but some other character. Can you check it with

CL_ABAP_CHAR_UTILITIES=>CR_LF