topic Re: variable type question in Application Development and Automation Discussions

variable type question

Former Member — Fri, 07 Jul 2006 13:30:19 GMT

Hi,

my requirements are the following :

I must have variable with f.e a fixed length of 10.

In this variable a value will be put with a variable length.

If this length is smaller then 10, the remaining characters must be filled up with spaces, so that the actual length is always 10.

Is there a variable type that supports this ? How must i achieve this ?

with regards

Erik Dierinck

Re: variable type question

RichHeilman — Fri, 07 Jul 2006 13:31:16 GMT

You can define your length in the data statement. Doing so makes this field always a length of 10.

data: variable(10) type c.

Regards,

Rich Heilman

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:34:10 GMT

u can declare the variable as below

data text(10) type n.

but text will always have leading zeroes and not spaces.

Sample code

PARAMETER: ckb1(10) TYPE n.

DATA: len1 TYPE i.

len1 = STRLEN( ckb1 ).

MESSAGE i000(vz) WITH len1.

-Kiran

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:37:19 GMT

declare as type n.

data: v_num(10) type n value '10'.

write: v_num.

Regards,

ravi

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:41:04 GMT

good

you can declare the variable as

data: variablename(10) type c.

then down check that variable in a loop whenever the data from the database will be less than 10 than use tha APPEND command to append 0 before that.

thansk

mrutyun

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:42:13 GMT

Hi Erik,

Use Character type for your requirement.

Declare it as

DATA : var(10) TYPE C.

Consider this program,


REPORT zarun_2.

DATA : char(10) TYPE c,
       len TYPE i.

char = 'TEST'.
len = STRLEN( char ).
WRITE : / char, 13 'Length:', len.

CLEAR char.
char = 'TESTSDN'.
len = STRLEN( char ).
WRITE : / char, 13 'Length:', len.

CLEAR char.
char = 'TESTSDNSAP'.
len = STRLEN( char ).
WRITE : / char, 13 'Length:', len.

Regards,

Arun Sambargi.

Message was edited by: Arun Sambargi

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:48:52 GMT

Hi,

Declare as type n.


data: num(10) type n .
num = '1'.
write: num.

Regards

vijay

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:52:34 GMT

Okay,

But will this also work with a concatenation :

suppose i have three variables

var1(10) = 'test'

var1 ='test1'

var2 ='test2'

the result of the concatenation must be

"test test1 test2"

with regards

Re: variable type question

RichHeilman — Fri, 07 Jul 2006 13:55:13 GMT

What exactly is the requirement. Do you need to have some space in your result field?

Regards,

Rich Heilman

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:57:02 GMT

Yes

Re: variable type question

Former Member — Fri, 07 Jul 2006 13:58:54 GMT

Hi,

you can do this way...

REPORT  ZZSDSDF                                 .

data: v1(10),v2(10),v3(10),v(30).

v1(10) = 'test'.
v2 = 'test1'.
v3 = 'test2'.
v = v1.
v+10(10) = v2.
v+20(10) = v3.

write v.

Regards

vijay

Re: variable type question

Former Member — Fri, 07 Jul 2006 14:00:19 GMT

Hi Erik,

You can do it in this way.


REPORT zarun_2.

DATA :  char1(10) TYPE c,
        char2(10) TYPE c,
        char3(10) TYPE c,
       result(30) TYPE c. " Or can use type <b>STRING</b>

char1 = 'test'.
char2 = 'test1'.
char3 = 'test2'.

CONCATENATE char1 char2 char3 INTO result <b>SEPARATED BY space.</b>

WRITE result.

Regards,

Arun Sambargi.

Message was edited by: Arun Sambargi

Re: variable type question

RichHeilman — Fri, 07 Jul 2006 14:03:14 GMT

You will need to give a placeholder during concatenation, then you can get rid of it.



report zrich_0001.

data: var1(10) type c,
      var2(10) type c,
      var3(30) type c,
      result(30) type c.

var1 = 'Tst1'.
var2 = 'Tst2'.
var3 = 'Tst3'.

translate var1 using ' %'.
translate var2 using ' %'.
translate var3 using ' %'.

concatenate var1 var2 var3 into result.

translate result using '% '.

write:/ result.

Regards,

Rich heilman