topic Re: replace in a string in Application Development and Automation Discussions

replace in a string

Former Member — Mon, 17 Jul 2006 06:52:19 GMT

Hi.

I need to remove som values in a string if it's longer than 18 char. The logic is as follows. If len > 18 start removing '-' from back of the string until (if possible) the length is 18.

I have probelms reaplcing from behind, any ideas?

/jon

Re: replace in a string

Former Member — Mon, 17 Jul 2006 06:55:06 GMT

Hi Jon,

Pls elaborate your requirement.

Regards

Shekhar

Re: replace in a string

Former Member — Mon, 17 Jul 2006 06:56:57 GMT

STRING = 'ABDCE'.

LEN = STRLEN( STRING ).

if len > 18.

use logic like that....

REPORT abc.

DATA : BEGIN OF itab OCCURS 0,

str(50),

END OF itab.

DATA : cha(50) VALUE 'cha-sek-jskjfsjf',

str(2000).

SPLIT cha AT '-' INTO TABLE itab.

loop at itab.

concatenate str itab-str into str separated by space.

endloop.

write : str.

Re: replace in a string

madan_ullasa — Mon, 17 Jul 2006 07:00:51 GMT

hi Jon,

try this.

data var_len type i, ch type c.

var_len = strlen of string.

if var_len > 18.

var_len = var_len - 1.

ch = string+var_len(1).

do var_len times.

if ch = '-'.

delete that character.

endif.

enddo.

this is just a rough logic... try this.

regards,

Madan..

Re: replace in a string

Former Member — Mon, 17 Jul 2006 07:08:31 GMT

Hi Jon,

Consider these code.

If you want to repalce all '-' with spaces and condense


REPORT  zztest_arun_1 .

DATA : string TYPE string.

START-OF-SELECTION.
string = 'sdfsadf--asdf-asd-asd-'.

IF STRLEN( string ) GT 18.

  TRANSLATE string USING '- '.
  CONDENSE string NO-GAPS.

ENDIF.

WRITE :  string.

If you want to repalce only '-' till length 18 form backwards with spaces and condense


  REPORT  zztest_arun_2 .

  DATA : string TYPE string,
         len TYPE i,
         off TYPE i.

  START-OF-SELECTION.
    string = 'sdfsadf--asdf-asd-asd-'.

    len =  STRLEN( string ).

    IF len GT 18.

      DO.

        IF  STRLEN( string ) GT 18.

          off = len - sy-index.

          REPLACE '-' IN SECTION OFFSET off LENGTH -1 OF string WITH space.
          CONDENSE string NO-GAPS.


        ELSE.

          EXIT.

        ENDIF.

      ENDDO.

    ENDIF.

    WRITE :  string.

Regards,

Arun Sambargi

Message was edited by: Arun Sambargi

Re: replace in a string

Former Member — Mon, 17 Jul 2006 07:31:30 GMT

Hi Jon

You can use the following code.

data: str(50 )type c.

data: len type i.

data: diff type i.

str = 'njiodjjjiojsjfgj----

len = strlen( str).

diff = len - 18.

if diff > 0.

SHIFT str RIGHT DELETING TRAILING '-'.

endif.

I think this must solve out yor problem. If problem presists do reply.

Re: replace in a string

Former Member — Mon, 17 Jul 2006 07:41:24 GMT

hi.

and thanks to everyone helping!

this does not quite do what i need.

ie. i could get a string looking like this:

1234-678-12-34-56789

It's 19 char long and i need to remove the last '-' so that the string will be 1234-678-12-3456789

when testing all the possible solutions i'm only able to remove all the '-'.

i was thinking about writing the string in reverse to a temp_string and just replace first occ. of '-', but i cant find a easy way to reverse the string either...

/jon