topic Statement IF in Application Development and Automation Discussions

Statement IF

d4xtian — Fri, 20 May 2022 16:14:09 GMT

HI I have question about my code...

i would like if one of my condition is true, i would it write the message with the variable is true

Thanks

IF P_LONG = 0 OR P_LARG = 0 OR P_HAUT = 0.
WRITE 'You can't put a 0'.
ELSE.
WRITE 'VALID'.
ENDIF.

Re: Statement IF

AlexGourdet — Fri, 20 May 2022 16:14:24 GMT

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Re: Statement IF

Sandra_Rossi — Fri, 20 May 2022 16:24:08 GMT

What your code does, is what you read: if one of the three is zero then "you can't put a 0", else "valid".

Could you explain your question please?

Re: Statement IF

matt — Fri, 20 May 2022 17:05:52 GMT

Have a little read about boolean logic, as you're making a common error by people who don't understand it.

Maybe AND would be your friend.

Re: Statement IF

d4xtian — Fri, 20 May 2022 20:42:15 GMT

I as the user to enter numerical data to make a calulation, and i don't want him to be able to put 0 in on of the field, and i would like to return error message to him in indicating the field or fiels where where he field in 0

Re: Statement IF

Sandra_Rossi — Sat, 21 May 2022 09:48:25 GMT

Or maybe you don't understand the concept of Types. Did you define P_LONG, P_LARG and P_HAUT with a numeric type? If not, probably your code won't work well.

Re: Statement IF

d4xtian — Sun, 22 May 2022 18:24:13 GMT

sorry Sarah, i haven’t post the Declaration part, i did it, declare it.

Data : P_LONG type i,

P_LARGE type i,

P_HAUT type i.

Re: Statement IF

Sandra_Rossi — Sun, 22 May 2022 19:07:45 GMT

So, yes, it's numeric type.

So, your code is correct, it corresponds to what you want to do.

Re: Statement IF

d4xtian — Sun, 22 May 2022 23:27:41 GMT

Yes but i want the message error gave me the name of the field and the field that has the '0'.

IF P_LONG = 0 OR P_LARG = 0 OR P_HAUT = 0.
WRITE P_LONG ' can't HAVE a 0'.
ELSE.
WRITE 'VALID'.
ENDIF.

The message i have is

' 0 You can't put 0'

I have declare the name of the field in "Text Elements"

Re: Statement IF

FredericGirod — Mon, 23 May 2022 05:31:19 GMT

So you have to test separatly each field :

IF p_long eq 0.
  write |P_LONG can't have a 0|.
ELSE.
  IF p_larg eq 0.
    write |P_LONG can't have a 0|.
  ELSE.
    IF p_haut eq 0.
      write |P_LONG can't have a 0|.
    ENDIF.
  ENDIF.
ENDIF.

Re: Statement IF

FredericGirod — Mon, 23 May 2022 05:35:56 GMT

or you could create a table of variables

something like (not tested).

DATA(ma_jolie_table) = VALUE ...( ( fieldname = 'P_LONG' ) (fieldname = 'P_LARG' ....).
LOOP AT ma_jolie_table
     INTO DATA(ls_ma_jolie_ligne).
  ASSIGN (ls_ma_jolie_ligne-fieldname) to field-symbol(<field>).
  CHECK <field> IS ASSIGN.
  IF <field> eq 0.
    write /1 |{ ls_ma_jolie_table-fieldname } can't have a 0|.
  ENDIF.
ENDLOOP.

Re: Statement IF

Sandra_Rossi — Mon, 23 May 2022 06:22:25 GMT

OK. Your question was not clear. You'd better give example of what you expect, like if user enters 0 in P_LONG, how to write:

P_LONG can't have a 0