topic Re: Open SQL array insert results in duplicate database records in Application Development and Automation Discussions

Open SQL array insert results in duplicate database records

Former Member — Fri, 30 Nov 2012 10:41:11 GMT

Hi,

When i am trying create Characteristic using tcode-CT04, i am getting short dump in SAPSQL_ARRAY_INSERT_DUPREC.

Runtime Errors SAPSQL_ARRAY_INSERT_DUPREC

Exception CX_SY_OPEN_SQL_DB

Short text
The ABAP/4 Open SQL array insert results in duplicate database records.

What happened?
Error in the ABAP Application Program

The current ABAP program "SAPLCTVB" had to be terminated because it has
come across a statement that unfortunately cannot be executed.

What can you do?
Note down which actions and inputs caused the error.

To process the problem further, contact you SAP system
administrator.

    Using Transaction ST22 for ABAP Dump Analysis, you can look
    at and manage termination messages, and you can also
    keep them for a long time.

Error analysis
    An exception occurred that is explained in detail below.
    The exception, which is assigned to class 'CX_SY_OPEN_SQL_DB', was not caugh
     in
    procedure "SAVE_DATA" "(FORM)", nor was it propagated by a RAISING clause.
    Since the caller of the procedure could not have anticipated that the
    exception would occur, the current program is terminated.
    The reason for the exception is:
    If you use an ABAP/4 Open SQL array insert to insert a record in
    the database and that record already exists with the same key,
    this results in a termination.

(With an ABAP/4 Open SQL single record insert in the same error
situation, processing does not terminate, but SY-SUBRC is set to 4.)

Information on where terminated
Termination occurred in the ABAP program "SAPLCTVB" - in "SAVE_DATA".
The main program was "RSM13000 ".

    In the source code you have the termination point in line 124
    of the (Include) program "LCTVBF58".
    The program "SAPLCTVB" was started in the update system.
    The termination is caused because exception "CX_SY_OPEN_SQL_DB" occurred in
    procedure "SAVE_DATA" "(FORM)", but it was neither handled locally nor declared
    in the RAISING clause of its signature.

The procedure is in program "SAPLCTVB "; its source code begins in line
24 of the (Include program "LCTVBF58 ".

Source Code Extract

Line SourceCde

123 if not it_cabnt_ins[] is initial.

>>>>> insert cabnt from table it_cabnt_ins.

125 clear ef_no_changes.

126 endif.

Please help me to resolve the issue.

Regards,

Pramila.V

Re: Open SQL array insert results in duplicate database records

ThomasZloch — Fri, 30 Nov 2012 10:44:32 GMT

Since this seems to be a problem with SAP standard code, you should first look for SAP notes. Did you do this already? What did you find?

Thomas

Re: Open SQL array insert results in duplicate database records

sandeep_katoch — Fri, 30 Nov 2012 10:47:18 GMT

Hi Pramila,

Check whether the key which you are using to pass the value is not duplicate.

During debugging check the values you are inserting and check in the table which is getting updated with the values that the value is pre existing or not.

Regards,

Sandeep

Re: Open SQL array insert results in duplicate database records

former_member193464 — Fri, 30 Nov 2012 10:50:00 GMT

note 196113 may help.

Re: Open SQL array insert results in duplicate database records

Former Member — Fri, 30 Nov 2012 10:51:00 GMT

Hi Thomas,

Thanks for your quick response.

I have checked the thread(http://scn.sap.com/message/8888265) and applied but no use.

Can you suggest me the related SAP Notes for metioned issue?

Regards,

Pramila.V

Re: Open SQL array insert results in duplicate database records

Former Member — Fri, 30 Nov 2012 12:14:40 GMT

Hi,

Thanks for your reply.Its working by implementing the above mentioned Note.

Regards,

Pramila.V

Re: Open SQL array insert results in duplicate database records

former_member1358242 — Wed, 13 Jul 2022 19:01:32 GMT

Hi im inserting the data into table(zhrt_student) program was sytactically correct but getting runtime error.

DATA: wa TYPE zhrt_student,

it TYPE TABLE OF zhrt_student.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Maheswari Chava'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Ashini Kammili'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Anitha Rangisetti'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Sumanjali S'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Vijaya Sravani B'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Nandini P'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Kavitha Gettiboyina'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

wa-cid = 'ABAP'.

wa-sid = 'SHADEADD2'.

wa-sname = 'Kavitha Gettiboyina'.

wa-doj = '02.07.2022'.

wa-laptop = 'N'.

APPEND wa TO it.

INSERT zhrt_student FROM TABLE it.

IF sy-subrc = 0. "SUBRC = 0 means success, else failed

MESSAGE 'record updated sucessfully' TYPE 'S'.

ELSE.

MESSAGE 'update failed' TYPE 'I'.

ENDIF.