topic Re: Replacing space with '.' in Application Development and Automation Discussions

Replacing space with '.'

Former Member — Thu, 05 Jul 2012 11:47:23 GMT

Hi experts,

I have a requirement in which I need to replace all the spaces in a string with '.'. When I write the below code it is throwing dumb ..

REPLACE all occurrences of ' ' IN LV_UNAME WITH '.' .

The error I am getting is

An exception occurred that is explained in detail below.

The exception, which is assigned to class 'CX_SY_REPLACE_INFINITE_LOOP', was

not caught and

therefore caused a runtime error.

The reason for the exception is:

In the running program "ZSREE_TEST32", the command "REPLACE ALL OCCURENCES

OF "' '" ... " was to be executed. However, field "' '" has the length 0,

which would have resulted in an endless loop. Therefore, the program

was terminated.

Please help.....

Re: Replacing space with '.'

laurent_fournier2 — Thu, 05 Jul 2012 11:57:56 GMT

As the dump says, you tried to replace the '' in an empty field.

try this.

If not lv_uname is initial.

replace all occ.......

endif.

regards.

Re: Replacing space with '.'

Former Member — Thu, 05 Jul 2012 12:05:31 GMT

Hi,

It is always good to use the syntax FIND before REPLACE.

FIND FIRST OCCURRENCE OF " " IN lv_uname.

If Sy-subrc = 0.

REPLACE ALL OCC...

endif.

if sy-subrc = 0, it means we have atleast one search string the field.

if sy-subrc NE 0, it means we dont have search sting in the field.

Cheers

~Niranjan

Re: Replacing space with '.'

Former Member — Thu, 05 Jul 2012 12:28:01 GMT

hi try to use this,

find space in LV_UNAME.

if sy-subrc eq 0.

REPLACE all occurrences of space IN LV_UNAME WITH '.' .

endif.

Re: Replacing space with '.'

Former Member — Thu, 05 Jul 2012 12:47:27 GMT

Try this.

do (n) times.

replace ' ' with '.' into (your string)

enddo.

n would be total words used in your string or if you sure string may not contain words more then 100 or 1000 or whatever then you can use fix number of loop ..i.e n = 10 or n = 100 or n = 1000.

Re: Replacing space with '.'

Former Member — Thu, 05 Jul 2012 13:07:13 GMT

Check the following link

http://scn.sap.com/thread/578006

and

http://scn.sap.com/thread/1321898

Re: Replacing space with '.'

Former Member — Thu, 05 Jul 2012 13:12:43 GMT

EDIT: IGNORE THIS POST. Krupa posted the correct answer.

Is lv_uname actually a string, or is it something with a set length like sy-uname? If its something with a fixed length, try this:

DATA: lv_uname TYPE syuname,
          lv_length TYPE i.
 
 lv_uname = 'John Doe'.
 
 lv_length = strlen( lv_uname ).
 DO lv_length TIMES.
   IF lv_uname+sy-index(1) IS INITIAL.
     lv_uname+sy-index(1) = '.'.
   ENDIF.
 ENDDO.

For some reason though, this code is adding an extra '.' at the very end of lv_uname. You can always remove that one character though:

lv_uname+lv_length(1) = space.

Re: Replacing space with '.'

Former Member — Thu, 05 Jul 2012 16:55:03 GMT

thank you guys,

i checked then link in krupa's post.it solved my my problem...

but i found another way to do it....

translate lv_uname using ' .' .

here we have to give a space before the dot in the single qotes..

regards ,

Noufal Rahman

Re: Replacing space with '.'

Former Member — Mon, 09 Jul 2012 13:50:35 GMT

Isn't that what the second link in Krupa's post told you to do? That's not another way, its the way that was recommending.

Re: Replacing space with '.'

MariaJooRocha — Mon, 09 Jul 2012 16:13:45 GMT

Hi,

Try

Translate lv_uname using ' . '.

Regards,

Maria João Rocha

Re: Replacing space with '.'

kesavadas_thekkillath — Tue, 10 Jul 2012 04:49:51 GMT

just change ' ' to ` `.