topic Re: Delete From String Variable in Application Development and Automation Discussions

Delete From String Variable

Former Member — Wed, 24 Feb 2010 07:21:47 GMT

Hi Experts,

I have one string variable.

data : inputstr type string value 'ABCDE'.

Now Based on this inputstr, i need to find different combinations. Like,

BCDE, ACDE, ABDE, ABCE.

So I need to read the string by the index, if index is one then i need to remove A from 'ABCDE' and

If the index is 2 then I need to remove B from 'ABCDE'.

Please give me your all valuable suggestions.

Thank in advance,

Helps will be appreciated.

Re: Delete From String Variable

Former Member — Wed, 24 Feb 2010 07:37:36 GMT

hii,

u can use REPLACE.

Re: Delete From String Variable

Former Member — Wed, 24 Feb 2010 07:39:18 GMT

Hi,


DATA: lv_input TYPE string.
DATA: lv_output TYPE string.
DATA: lv_output1 TYPE string.
DATA: lv_output2 TYPE string.
DATA: lv_index TYPE sy-index.
DATA: lv_length TYPE i.

lv_input = 'ABCDE'.
lv_length = STRLEN( lv_input ).

DO.
  lv_output1 = lv_input(lv_index).
  lv_output2 = lv_input.
  SHIFT lv_output2 BY lv_index PLACES.
  SHIFT lv_output2 BY 1 PLACES.

  CONCATENATE lv_output1 lv_output2 INTO lv_output.
  WRITE: lv_output, /.

  ADD 1 TO lv_index.
  IF lv_index EQ lv_length.
    EXIT.
  ENDIF.

ENDDO.

regards Marcel

Re: Delete From String Variable

SuhaSaha — Wed, 24 Feb 2010 07:47:17 GMT

Hello,

You can try this code snippet:

DATA v_str TYPE string.

DATA:
      v_str1(1000) TYPE c,
      v_str2(1000) TYPE c,
      v_len TYPE i,
      v_idx TYPE i.

v_str = 'ABCDEFGH'.

v_str1 = v_str.

v_len = STRLEN( v_str1 ).

DO v_len TIMES.
  v_idx = sy-index - 1.
  v_str2 = v_str1.

  v_str2+v_idx(1) = ` `.
  CONDENSE v_str2 NO-GAPS.
  WRITE: / v_str2.
  CLEAR v_str2.

ENDDO.

BR,

Suhas

Edited by: Suhas Saha on Feb 24, 2010 1:22 PM