topic Re: Problem with statement like in Application Development and Automation Discussions

Problem with statement like

former_member216100 — Mon, 26 Oct 2009 12:08:03 GMT

Dear all

when I do a select I can work with the statement like

CONCATENATE WA_DEL-FIELD '%' INTO I_FIELD.

      SELECT * FROM ZTABLE INTO TABLE IT_ITAB
        WHERE FIELD LIKE I_FIELD.

how do I can do the same question for a if command for a field ?

I was thinking with the statement (FIELD = ABCDEFG) (I_FIELD-SIGN = I / I_FIELD-OPTION = 'EQ' / I_FIELD-LOW = 'ABC*'

IF FIELD IN I_FIELD

should work, but it was not working..... what do I need to do

SuhaSaha — Mon, 26 Oct 2009 12:09:31 GMT

Hello,

Silly mistake ... You have to use the OPTION as CP ( C ontains P attern ) instead of EQ

(I_FIELD-SIGN = I / I_FIELD-OPTION = 'CP' / I_FIELD-LOW = 'ABC*'

BR,

Suhas

ThomasZloch — Mon, 26 Oct 2009 12:10:02 GMT

OPTION should be 'CP', not 'EQ'. You can also try the "CP" operator ("covers pattern")

Thomas

Former Member — Mon, 26 Oct 2009 12:11:05 GMT

Hi,

Change the I_FIELD-OPTION to CP insttead of EQ. It should work now

Vikranth

former_member216100 — Mon, 26 Oct 2009 12:14:12 GMT

it is to early in the morning... sorry guys and thanks for the support...... I should sleep longer.... have not seen that I did not use CP....

ThomasZloch — Mon, 26 Oct 2009 12:35:49 GMT

No Problem. Please remember the other guys as well, we all answered at the same time more or less

Thomas