topic Re: strlen problem in Application Development and Automation Discussions

strlen problem

Former Member — Wed, 23 Sep 2009 11:45:05 GMT

when i try to do strlen for

DATA lv_str2 TYPE string.
DATA lv_length2_str TYPE n.

lv_str2 = 'USER_AND_P' .

lv_length2 = strlen( lv_str2 ).


lv_length2_str = lv_length2.

lv_length2 = 10

and when i try to do the

lv_length2_str = lv_length2 stentment i dont get any value to lv_length2_str

wahy ?

Regards

chirs

Re: strlen problem

Former Member — Wed, 23 Sep 2009 11:48:51 GMT

Hi,

type n acts like a c..you need to define leght..



DATA lv_str2 TYPE string.
DATA lv_length2_str      TYPE n.  "old statement
 DATA lv_length2_str(3) TYPE n.  "new statemnet ..pass 3 in the bracket
      "or
DATA lv_length2 TYPE INT2. 

 lv_str2 = 'USER_AND_P' .
 
 lv_length2 = strlen( lv_str2 ).
 
 
 lv_length2_str = lv_length2.

Prabhudas

Re: strlen problem

GauthamV — Wed, 23 Sep 2009 11:49:26 GMT

Try this.


DATA lv_str2 TYPE string.
DATA lv_length2_str TYPE i.
DATA lv_length2 TYPE i.

lv_str2 = 'USER_AND_P' .

lv_length2 = strlen( lv_str2 ).


lv_length2_str = lv_length2.

write: lv_length2_str.

Re: strlen problem

bpawanchand — Wed, 23 Sep 2009 11:53:09 GMT

DATA lv_length2_str TYPE n.

Because you have declared the type as NUMERIC of size 1, so may be while you are trying to assign the varibale then you will not get the right value.

Re: strlen problem

Former Member — Wed, 23 Sep 2009 12:00:26 GMT

HI Prabhu,

it's work but why?

regards

Chris

Re: strlen problem

Former Member — Wed, 23 Sep 2009 12:03:10 GMT

When declared as TYPE N without the length specification, it will take the default length as only one. But the length you got was 10. So it must be storing only 1. When you declared it with length as 3, its taking the whole value as 10. Thats the difference