topic Re: Type p length in Application Development and Automation Discussions

Type p length

Former Member — Fri, 25 Sep 2009 01:28:23 GMT

I have a statement like this is one of the old report:

WRITE: /06 33 v_rej1, 45  v_%rej2, 57 v_rej3.

I getting the output:

35.42       90.00      100.00

I had to place a gap of 12 in between... but I need the values side by side with my specific values spaces in between.

WRITE: /06 33 v_rej1, 38  v_%rej2, 43 v_rej3.

the next value on right is closing the before value... I cannot convert the values to type c and display. Plz let me know some add on for write where I can have my values side by side.

Re: Type p length

venkat_o — Fri, 25 Sep 2009 03:02:18 GMT

Hi Ram Kumar, Try this way.


REPORT ztest_notepad.
DATA:v_rej1  TYPE p DECIMALS 2 VALUE '35.42',
     v_%rej2 TYPE p DECIMALS 2 VALUE '90.00',
     v_rej3  TYPE p DECIMALS 2 VALUE '100.00'.
DATA:v_rej1_c(15)  TYPE c,
     v_%rej2_c(15) TYPE c,
     v_rej3_c(15)  TYPE c.
DATA :str TYPE string.
WRITE:v_rej1   to v_rej1_c LEFT-JUSTIFIED,
      v_%rej2  to v_%rej2_c LEFT-JUSTIFIED,
      v_rej3   to v_rej3_c LEFT-JUSTIFIED.
CONCATENATE v_rej1_c
            v_%rej2_c
            v_rej3_c INTO str SEPARATED BY space.

WRITE: / v_rej1,v_%rej2,v_rej3.
WRITE: / v_rej1_c,v_%rej2_c,v_rej3_c.
WRITE:/ str.

Thanks Venkat.O

Re: Type p length

Former Member — Fri, 25 Sep 2009 22:21:04 GMT

left-justified worked.