topic Re: How to insert record inside the internal table in below code in Application Development and Automation Discussions

How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 05:33:06 GMT

Hi all,

My requirement is to find the sub-total and need to insert in between the internal table.

You can see the output ....where I want the sub-total F2 when 1 & 2 combindely , 3 , 4& 5 combindely .Please check it and let me know is it possible

when i am using modification it is not creating extra row inside the table instead it is modifying one row and putting the total there.

For ex: the origianl output is

F1 F2 F3

A 1 1

B 1 1

F 2 1

D 3 1

E 4 1

C 5 1

We want to display all the total of f2 of 1-2 , 3 , 4-5

so expcected output is

F1 F2 F3

A 1 1

B 1 1

F 2 1

* 3 ->This is the sub-total of 1& 2 of f2

D 3 1

* 1 ->this is the sub-total of 3

E 4 1

C 5 1

* 2 -> this is the sub-total of 4 & 5

= space

But coming output is

A 1 1

B 1 1

* 3 -> it is modifying the F row and inserting the total .Total is comong correct but is shoule insert instead of modifying the record!!
* 1

E 4 1

Please help how to insert the row total at the end of the chage of field

Please find the below code ..Due to space problem i am attaching below

Sas

Re: How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 05:35:06 GMT


REPORT  YTEST_MODIFY.

data: begin of itab occurs 1,
TOT TYPE C,
f1 type c,
f2 type c,
f3 type i ,
end of itab.

data: begin of Jtab occurs 1,
f1 type c,
f2 type c,
f3 type i ,
end of Jtab.
START-OF-SELECTION.
ITAB-f1 = 'A'.ITAB-F2 =  1.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'B'.ITAB-F2 =  1.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'C'.ITAB-F2 =  5.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'D'.ITAB-F2 =  3.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'E'.ITAB-F2 =  4.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'F'.ITAB-F2 =  2.ITAB-F3 =  1.
APPEND ITAB.
SORT ITAB BY F2.

LOOP AT ITAB.
WRITE:/ ITAB-F1 ,8 ITAB-F2 , ITAB-F3.
ENDLOOP.

LOOP AT ITAB.
IF ITAB-F2 = 1 OR ITAB-F2 = 2.
ITAB-TOT = 1.
MODIFY ITAB.
ELSEIF ITAB-F2 = 3.
ITAB-TOT = 3.
MODIFY ITAB.
ELSEIF ITAB-F3 = 4 OR ITAB-F3 = 5.
ITAB-TOT = 4.
MODIFY ITAB.
ENDIF.
ENDLOOP.

DATA: A TYPE I , B .

LOOP AT ITAB.
IF B = 0.
A = A + ITAB-F3.
ENDIF.
AT END OF TOT.
MOVE SPACE TO ITAB-F1.
MOVE SPACE TO ITAB-F2.
MOVE A TO ITAB-F3.
MODIFY ITAB .
CLEAR A.
B = 1.
ENDAT.

B = 0.
ENDLOOP.



LOOP AT ITAB.
MOVE-CORRESPONDING ITAB TO JTAB.
APPEND JTAB.
ENDLOOP.

ULINE.
LOOP AT JTAB.
WRITE: / JTAB-F1 , JTAB-F2 , JTAB-F3.
ENDLOOP.

Re: How to insert record inside the internal table in below code

kesavadas_thekkillath — Wed, 15 Jul 2009 05:39:30 GMT

by which field you are grouping

1and 2

4 and 5

Re: How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 05:46:04 GMT

SaS,

You might have to do something [similer|; where i was intended to do so for Sub-total text.

Re: How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 05:50:32 GMT

You can see the output ....where I want the sub-total F2 when 1 & 2 combindely , 3 , 4& 5 combindely .

Hi Sas,

On what basis do you decide for which fields of F2 you have to sum F3? as in how have you decided 1-2,3,4-5...?

whats is the sequence?

Regards,

Sumit Nene

Re: How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 06:12:43 GMT

hi Kulesh,

Consider F2 as Emp group where we HR need to identify the totals of emp gorup 1& 2 and 3 and 4&5 how many people are there.,....

So this is my requirement and F3 is the Total field which need to be inserted in between of the internal table...

So i hope you understand my requirement.....

Amit that thread is TOO vast and too complicated i guess...

Actually a small change i need to put in my previous code...

instead of modify i need to put insert is working but it is inserting above the end of Field...

But to insert in the appropraite line how ???will copy paste the code in next thread

Sas

Re: How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 06:25:06 GMT

Here is the solution ....i Got the answer Thanks for your helping hands friends


REPORT  YTEST_MODIFY.

DATA: BEGIN OF ITAB OCCURS 1,
TOT TYPE C,
F1 TYPE C,
F2 TYPE C,
F3 TYPE I ,
END OF ITAB.

DATA: BEGIN OF JTAB OCCURS 1,
F1 TYPE C,
F2 TYPE C,
F3 TYPE I ,
END OF JTAB.



START-OF-SELECTION.


  ITAB-F1 = 'A'.
  ITAB-F2 =  1.
  ITAB-F3 =  1.
  APPEND ITAB.

  ITAB-F1 = 'B'.
  ITAB-F2 =  1.
  ITAB-F3 =  1.
  APPEND ITAB.

  ITAB-F1 = 'C'.
  ITAB-F2 =  5.
  ITAB-F3 =  1.
  APPEND ITAB.

  ITAB-F1 = 'D'.
  ITAB-F2 =  3.
  ITAB-F3 =  1.
  APPEND ITAB.

  ITAB-F1 = 'E'.
  ITAB-F2 =  4.
  ITAB-F3 =  1.
  APPEND ITAB.

  ITAB-F1 = 'F'.
  ITAB-F2 =  2.
  ITAB-F3 =  1.
  APPEND ITAB.

  SORT ITAB BY F2.

  LOOP AT ITAB.
    WRITE:/1 ITAB-F1 ,
          8 ITAB-F2 ,
          10 ITAB-F3 .
  ENDLOOP.

  LOOP AT ITAB.
    IF ITAB-F2 = 1 OR ITAB-F2 = 2.
      ITAB-TOT = 1.
      MODIFY ITAB.
    ELSEIF ITAB-F2 = 3.
      ITAB-TOT = 3.
      MODIFY ITAB.
    ELSEIF ITAB-F2 = 4 OR ITAB-F2 = 5.
      ITAB-TOT = 4.
      MODIFY ITAB.
    ENDIF.
  ENDLOOP.


  SKIP 2.

  SORT ITAB BY TOT.

  DATA : L_SUM(2) TYPE C,
         L_ROW(2) TYPE C.

  LOOP AT ITAB.
    MOVE-CORRESPONDING ITAB TO JTAB.
    APPEND JTAB.
    L_SUM = L_SUM + ITAB-F3 .

    AT END OF TOT.
      CLEAR JTAB.
      JTAB-F3 = L_SUM .
      APPEND JTAB.
      CLEAR L_SUM.
    ENDAT.

  ENDLOOP.

  LOOP AT JTAB.
    WRITE:/1 JTAB-F1 ,
          8 JTAB-F2 ,
          10 JTAB-F3 .
  ENDLOOP.

*  DATA: a TYPE i , b .
*
*  LOOP AT itab.
*    IF b = 0.
*      a = a + itab-f3.
*    ENDIF.
*    AT END OF tot.
*      MOVE space TO itab-f1.
*      MOVE space TO itab-f2.
*      MOVE a TO itab-f3.
*      MODIFY itab .
*      CLEAR a.
*      b = 1.
*    ENDAT.
*
*    b = 0.
*  ENDLOOP.
*
*
*
*  LOOP AT itab.
*    MOVE-CORRESPONDING itab TO jtab.
*    APPEND jtab.
*  ENDLOOP.
*
*  ULINE.
*  LOOP AT jtab.
*    WRITE: / jtab-f1 , jtab-f2 , jtab-f3.
*  ENDLOOP.

Re: How to insert record inside the internal table in below code

Former Member — Wed, 15 Jul 2009 06:47:19 GMT

hii ssaplove,

check the following code, its working in my system..

*&---------------------------------------------------------------------*
*& Report  ZTEST09
*&
*&---------------------------------------------------------------------*
*&
*&
*&---------------------------------------------------------------------*

REPORT  ZTEST09.

data total type i.
data n type sy-tabix.
data m type sy-tabix.
data p type sy-tabix.

data: begin of itab occurs 1,
TOT TYPE C,
f1 type c,
f2 type c,
f3 type i ,
end of itab.

data: begin of Jtab occurs 1,
f1 type c,
f2 type c,
f3 type i ,
end of Jtab.
START-OF-SELECTION.
ITAB-f1 = 'A'.ITAB-F2 =  1.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'B'.ITAB-F2 =  1.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'C'.ITAB-F2 =  5.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'D'.ITAB-F2 =  3.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'E'.ITAB-F2 =  4.ITAB-F3 =  1.
APPEND ITAB.
ITAB-f1 = 'F'.ITAB-F2 =  2.ITAB-F3 =  1.
APPEND ITAB.
SORT ITAB BY F2.

loop at itab where f2 = 1 or f2 = 2.
n = sy-tabix.
total = total + itab-f3.
endloop.

n = n + 1.
CLEAR itab.
itab-tot = total.
 insert itab index n.
 clear total.
clear itab.
loop at itab from n where f2 = 3.
  m = sy-tabix.
  total = total + itab-f3.
endloop.


m = m + 1.
CLEAR itab.
itab-tot = total.
 insert itab index m.
 clear total.
clear itab.

loop at itab from m where f2 = 4 or f2 = 5.
  p = sy-tabix.
  total = total + itab-f3.
endloop.

p = p + 1.
CLEAR itab.
itab-tot = total.
 insert itab index p.
 clear total.
clear itab.

 LOOP AT itab.
 write:/ itab-f1 , itab-f2, itab-f3,itab-tot..
 endloop.

*&---------------------------------------------------------------------*
*&      Form  Sub_total
*&---------------------------------------------------------------------*
*       text
*----------------------------------------------------------------------*
*  -->  p1        text
*  <--  p2        text
*----------------------------------------------------------------------*