topic Re: Alternative for REPLACE in Application Development and Automation Discussions

Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 11:19:12 GMT

I am using the following syntax of REPLACE in a report.

REPLACE old_character IN my_object WITH new_character.

The unique thing about this report is that it has to run

on different versions from 46c.

The above syntax works ok in abap version 7 but is not downward compatible to 46c.

Can anybody suggest something (of similar functionality) which will work across releases.

Will the older syntax of replace do?

REPLACE old_character WITH new_character INTO my_object.

(Abap help says this is obsolete.)

Any possible help is very much appreciated.

Regards

Sahir

Re: Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 11:29:32 GMT

HI,

Build logic using search ,overlay,move.

Regards

Amole

Re: Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 11:31:47 GMT

you need to use split and concatenate.

regards

vijay

Re: Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 11:40:47 GMT

Hope this works...

DATA text(16) VALUE 'THIS IS OLD TEXT'.
DATA new_str(25).
DATA temp(25).
DATA old_char(16) VALUE 'OLD'.
DATA new_char(16) VALUE 'NEW'.
DATA off TYPE i VALUE 0.
DATA moff TYPE i.
DATA mlen TYPE i.
DATA len TYPE i.
DATA flag TYPE i VALUE 0.


len = strlen( new_char ).

DO.
flag = 0.

FIND old_char IN SECTION
  OFFSET off OF text
  MATCH OFFSET moff
  MATCH LENGTH mlen
  .

IF sy-subrc = 0.
  flag = 1.
  WRITE : moff, mlen.
ENDIF.

IF flag = 0.
  off = off + mlen.
  WRITE : / text+off.
  CONCATENATE new_str text+off INTO new_str SEPARATED BY SPACE.
  EXIT.

ENDIF.

*Change repl

CONCATENATE new_str text+off(moff) INTO new_str.
CONCATENATE new_str new_char INTO new_str SEPARATED BY SPACE.

off = moff + 1.

ENDDO.
WRITE / new_str.

Ps: Reward points if helpful.

Re: Alternative for REPLACE

abdul_hakim — Mon, 30 Jan 2006 11:41:20 GMT

Use REPLACE A1 WITH A2 INTO A3 syntax variant..

Abdul

Re: Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 12:10:03 GMT

Hi,

This one replaces all occurances of an old char with new char using no special commands .

data : my_obj(100) value 'This is Old Text', new_char value 'a' ,
old_char value 'i'.
data : x type i value 1, y type i, len type i.
describe field my_obj length len in byte mode.


while y ne len.
 if my_obj+y(x) eq old_char.
     my_obj+y(x)  = new_char.
 endif.
y = y + 1.
endwhile.

write : my_obj.

reward points if helpful

Re: Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 12:29:37 GMT

I would like to clarify something.

I am trying to replace one string with another in a big string. (Not characters, as i mentioned in the earlier message, sorry for that!)

Thanks for all the replies. I am trying out some of them.

Regards

Sahir

Re: Alternative for REPLACE

Former Member — Mon, 30 Jan 2006 12:34:56 GMT

Hi Sahir,

the code given above is can be applied to string of any length and even string replacements can be done using the same operation.

this minor change in the previous code ca be made.

data : my_obj(100) value 'This is Old Text', new_char(100) value 'abcd' ,old_char(100) value 'is' ,str1(100),str2(100).

data : x type i value 1, y type i, len type i , idx type i , offset like sy-index.

describe field my_obj length len in byte mode.

while y ne len.

if my_obj+y(x) eq space.

while my_obj+y(x) ne space or y eq len.

flag = 1.

offset = sy-index.

if my_objy(x) eq old_charidx(x).

continue.

else.

flag = 0.

endif.

y = y + 1.

idx = sy-index.

endwhile.

y = sy-index.

endwhile.

if flag = 1.

str1 = my_obj+(offset).

str2 = my_obj+idx(*).

concatenate str1 new_char str2 into my_obj seperated by spaces.

write : my_obj.

please Award points if the answer is helpful