topic Re: last characters in Application Development and Automation Discussions

last characters

Former Member — Fri, 27 Mar 2009 07:03:49 GMT

hi sap,

i have a field - objnr -ISTR030000001000007

i need to take out the first 12 characters and keep the last 7 characters.

so how can i do it can you pls tell me

regards,

laya.

Re: last characters

I355602 — Fri, 27 Mar 2009 07:07:39 GMT

Hi,

You can use the offset technique.

Refer:


data : objnr type objnr. "length for objnr is 18

objnr = 'STR030000001000007'.

data : v_str(10) type c.

v_str = objnr+11(7).

write : v_str, objnr.

Regards,

Tarun

Re: last characters

Former Member — Fri, 27 Mar 2009 07:08:17 GMT

Use offsets.

data : v_str1 type string value 'ISTR030000001000007' ,
         v_str2 type(12) type c,
         v_str3 type(7) type c.

v_str2 = v_str1+0(12).
v_str3= vstr1+13(7).

Write: v_str2, v_str3.

Thanks

Re: last characters

Former Member — Fri, 27 Mar 2009 07:11:05 GMT

Hi,

Try this Way..

DATA : l_len TYPE i.
DATA: l_value(7) TYPE c.
DATA l_objnr TYPE CHAR30.
l_objnr = 'ISTR030000001000007'.
l_len = STRLEN( l_objnr ).

l_len = l_len - 7 .

l_value = l_objnr+l_len(7).
WRITE l_value.

Re: last characters

Former Member — Fri, 27 Mar 2009 07:11:45 GMT

Hi,

For this particular case use:

data: v_objnr(7) type c.

v_objnr = objnr+12(7).

Regards.

Re: last characters

Former Member — Fri, 27 Mar 2009 07:14:10 GMT

Hi,

This is simple, hope below code snippet help you out:

data:objnr(19) value 'ISTR030000001000007',
       val(7) tyep c.
val = objnr+12(7).

write:/ val.

Pooja

Re: last characters

Former Member — Fri, 27 Mar 2009 08:15:18 GMT

This message was moderated.