topic Re: Find . in a string in Application Development and Automation Discussions

Find . in a string

Former Member — Tue, 07 Apr 2009 09:13:17 GMT

Hi,

I have a string which contains 43.555.

I would like to find the number occurred after a ".".

Let me know which function to use.

Re: Find . in a string

Former Member — Tue, 07 Apr 2009 09:16:08 GMT

search '.' in YOUR_STRING.

the position of your dot is beeing published in sy-fdpos, if found.

Strlen( YOUR_STRING ) gives you the length of your string.

length of string - position of dot = number of characters after dot.

Re: Find . in a string

Former Member — Tue, 07 Apr 2009 09:16:40 GMT

u can try to do:

split text at '.' into text1 text2.

not sure if it woks with numbers tho.

Re: Find . in a string

Former Member — Tue, 07 Apr 2009 09:18:09 GMT

Use split at dot, it wud be diveded into left and right strings then search the right number for ur pattern or number whatever u want

Re: Find . in a string

Former Member — Tue, 07 Apr 2009 09:20:04 GMT

Hi,

Try this.

Data : temp type string.

move num to temp. "num will hold 45.9999

split temp at '.' into str1 str2.

regards,

mallika

Re: Find . in a string

awin_prabhu — Tue, 07 Apr 2009 09:20:32 GMT

Check this code.

REPORT zsample.

DATA: s TYPE string,

off TYPE i,

w type c.

s = '43.555'.

FIND '.' IN s MATCH OFFSET off.

off = off + 1.

w = s+off(1).

write: w.

Re: Find . in a string

Former Member — Tue, 07 Apr 2009 09:23:07 GMT

hi Krish,

You can do like this..

split text at '.' into t1 t2.

and then you can find the length of t2.

Regards,

Nitin

Re: Find . in a string

Former Member — Tue, 07 Apr 2009 09:28:20 GMT

Hi,

Please use the following code:

DATA test type string.

DATA: num1 type string, num2 type string.

test = '43555'.

SPLIT test at '.' INTO num1 num2.

IF num2 is NOT INITIAL.

write: num2+0(1). -

> This will give you the number after '.' 5

ENDIF.

inside IF.. ENDIF

write: num2. -

> This will give the numbers after '.'. 555

Best Regards,

Suresh