topic Re: Adding strings in Application Development and Automation Discussions

Adding strings

Former Member — Thu, 04 Dec 2008 07:13:53 GMT

I have to add 2 variable like N000000006 AND N000000001, so that i get the result N000000007.

I tried out with soo many method, removing leading N , THEN 0 but still I am not able to get this result.

Re: Adding strings

Former Member — Thu, 04 Dec 2008 07:16:52 GMT

Remove 'N' and after that move rest number to other variable which if of type Interger and then add two variables. Again concatenate 'N' and sum and move that to original variable.

Regards,

Aparna.

Re: Adding strings

Former Member — Thu, 04 Dec 2008 07:21:41 GMT

Hi Priya..

Whats the datatype of N000000006 and N000000001.....

Regards

Re: Adding strings

Former Member — Thu, 04 Dec 2008 07:23:44 GMT

data : var1(10) type c,
         var2(10) type c,
         l_result type i,
         l_char(9) type c,
         l_digits type i.

var1 = 'N000000001'.
var2 = 'N000000006'.

l_result = var1+1(9) +  var2+1(9).
l_char = l_result.

condense l_char no-gaps.

l_digits = strlen( l_char ).

l_digits = 9 - l_digits.

check l_digits > 0.

do l_digits times.
concatenate '0'
l_char
into l_char.
condense l_char no-gaps.
enddo.

concatenate 'N'
l_char
into l_char.
condense l_char no-gaps.

Regards,

Mohaiyuddin

Re: Adding strings

Former Member — Thu, 04 Dec 2008 07:26:05 GMT

I have to add 2 variable like N000000006 AND N000000001, so that i get the result N000000007.

I tried out with soo many method, removing leading N , THEN 0 but still I am not able to get this result.c

First remove the N, by using var11(9) and var21(9)

Then remove leading zeroes

Then use WRITE statement : WRITE var3 (TYPE C) to var4 (TYPE P)

Then add the two variables

Then convert result to type C using WRITE var5 (TYPE P) to var6(TYPE C)

Then add leading zeroes

Then add leading N

Thats it really !!!!

Re: Adding strings

Former Member — Thu, 04 Dec 2008 07:26:22 GMT

Hi,

try this

parameters:
 p_num1(10) type c,
 p_num2(10) type c.

 data:
  w_val1(9) type n,
  w_val2(9) type n,
  w_result(9) type n,
  W_final(10)  type C.


  w_val1 = p_num1+1.
  w_val2 = p_num2+1.

  w_result = w_val1 + w_val2.

 concatenate 'N' w_result into W_final.
 write:W_final

Put any NXXXXXXXXX number of 9 digit in the parameters you will get your desired result.

Regards,

Anirban

Re: Adding strings

Former Member — Thu, 04 Dec 2008 07:38:53 GMT

DATA: l_input1(10) TYPE c VALUE 'N000000001',

l_input2(10) TYPE c VALUE 'N000000006',

l_output(10) TYPE c.

DATA: l_output1(9) TYPE n,

l_output2(9) TYPE n,

l_output3(9) TYPE n.

SHIFT l_input1 LEFT DELETING LEADING 'N'.

SHIFT l_input2 LEFT DELETING LEADING 'N'.

MOVE l_input1 to l_output1.

MOVE l_input2 to l_output2.

l_output3 = l_output1 + l_output2.

CONCATENATE 'N' l_output3 INTO l_output.

WRITE: l_input1, l_input2.

WRITE: l_output1, l_output2, l_output3.

*MOVE l_output3 to l_output.

WRITE: l_output.

Re: Adding strings

Former Member — Thu, 04 Dec 2008 08:22:08 GMT

Hi Priya,

try this out

DATA : var TYPE string VALUE 'N000000006',

var1 TYPE string VALUE 'N000000001',

str(10)," TYPE string,

str1(10)," TYPE string,

str2(10), "TYPE string,

len TYPE i.

len = STRLEN( var ) - 1.

str = var+0(1).

str1 = var+1(len).

len = STRLEN( var1 ) - 1.

str = var+0(1).

str2 = var1+1(len).

DATA : str3(10)." TYPE string.

str3 = str1 + str2.

data len2 type i.

*CONCATENATE str str3 INTO str.

len2 = strlen( str3 ).

len = len - 1.

condense str3 no-gaps.

data : new(10).

do len times .

concatenate '0' new into new.

enddo.

concatenate str new str3 into str.

IF sy-subrc IS INITIAL.

ENDIF.

regards

Ramchander Rao.K