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    <title>topic Custom table data entry in Application Development and Automation Discussions</title>
    <link>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535296#M1071712</link>
    <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Hi All, &lt;/P&gt;&lt;P&gt;I have a scenario...&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;where I have three key fields in my table: zgrp, zrole and zdate and two non key fields zdatum and zpur&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Now I want to enter the following records:&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;1&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2006&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;2&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;3&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 2&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; abc&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;1&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 2&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; abc&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;2&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;but I am not being able to insert these records, as soon as I enter the first record it gives me the follwoing error:&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;"An entry already exists with the same key"&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Thanks, &lt;/P&gt;&lt;P&gt;Rajeev&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
    <pubDate>Mon, 06 Oct 2008 14:37:34 GMT</pubDate>
    <dc:creator>Former Member</dc:creator>
    <dc:date>2008-10-06T14:37:34Z</dc:date>
    <item>
      <title>Custom table data entry</title>
      <link>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535296#M1071712</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Hi All, &lt;/P&gt;&lt;P&gt;I have a scenario...&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;where I have three key fields in my table: zgrp, zrole and zdate and two non key fields zdatum and zpur&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Now I want to enter the following records:&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;1&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2006&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;2&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;3&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 2&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; abc&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;1&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 2&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; abc&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;P&gt;zdatum-&amp;gt;12/11/2007&lt;/P&gt;&lt;P&gt;zpur-&amp;gt;2&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;but I am not being able to insert these records, as soon as I enter the first record it gives me the follwoing error:&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;"An entry already exists with the same key"&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Thanks, &lt;/P&gt;&lt;P&gt;Rajeev&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Mon, 06 Oct 2008 14:37:34 GMT</pubDate>
      <guid>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535296#M1071712</guid>
      <dc:creator>Former Member</dc:creator>
      <dc:date>2008-10-06T14:37:34Z</dc:date>
    </item>
    <item>
      <title>Re: Custom table data entry</title>
      <link>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535297#M1071713</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;How about looking in the table with SE16 to see what's already in there?&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;edit.&lt;/P&gt;&lt;P&gt;By the way: even if you manage to insert the first one, other's will go wrong. Given your examples: your primary key is not unique.&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Mon, 06 Oct 2008 14:41:04 GMT</pubDate>
      <guid>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535297#M1071713</guid>
      <dc:creator>Former Member</dc:creator>
      <dc:date>2008-10-06T14:41:04Z</dc:date>
    </item>
    <item>
      <title>Re: Custom table data entry</title>
      <link>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535298#M1071714</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;The table has just one recoed that I entered !!!!&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Mon, 06 Oct 2008 14:42:43 GMT</pubDate>
      <guid>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535298#M1071714</guid>
      <dc:creator>Former Member</dc:creator>
      <dc:date>2008-10-06T14:42:43Z</dc:date>
    </item>
    <item>
      <title>Re: Custom table data entry</title>
      <link>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535299#M1071715</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Hello ,&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;The first 3 entries that you want to add to you table all have exactly the same values for the key field.  That is why you are getting the error. &lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;You will need to rethink the keys that are needed for you table.  You may need to add another key field to make the entries in you table unique by those key values.&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Regards&lt;/P&gt;&lt;P&gt;Greg Kern&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Mon, 06 Oct 2008 14:44:45 GMT</pubDate>
      <guid>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535299#M1071715</guid>
      <dc:creator>Former Member</dc:creator>
      <dc:date>2008-10-06T14:44:45Z</dc:date>
    </item>
    <item>
      <title>Re: Custom table data entry</title>
      <link>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535300#M1071716</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;you need one more key field to build an unique key: i.e. zcount type numc4 so you could add from 1 to 9999 records with eaqual keys.&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;you can not add a second record with key&lt;/P&gt;&lt;P&gt;zgrp - &amp;gt; 1&lt;/P&gt;&lt;P&gt;zrole-&amp;gt; xyz&lt;/P&gt;&lt;P&gt;zdate-&amp;gt;12/12/2008&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Mon, 06 Oct 2008 14:48:38 GMT</pubDate>
      <guid>https://community.sap.com/t5/application-development-and-automation-discussions/custom-table-data-entry/m-p/4535300#M1071716</guid>
      <dc:creator>former_member226519</dc:creator>
      <dc:date>2008-10-06T14:48:38Z</dc:date>
    </item>
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